2

如何将对象数组拆分为对象数组?

说我想分成4组,我该怎么做?

[a,b,c,d,e,f,g,h] => [a,b] [c,d] [e,f] [g,h]

或者如果我指定我想分成 3 组,那么结果应该是 [a,b,c], [d,e,f], [g,h]

如果 h 不存在,它也应该工作。

4

3 回答 3

2

试试这个逻辑......

NSArray *arr = [[NSArray alloc]initWithObjects:@"One",@"Two",@"Three",@"Four",@"Five",@"Six",@"Seven",nil];
NSMutableArray *arrNew = [[NSMutableArray alloc]init];
int numberofSubArrs = 3; // change this to check the logic
for (int i=0; i<numberofSubArrs; i++) {
    NSMutableArray *arrrr = [[NSMutableArray alloc]init];
    [arrNew addObject:arrrr];
}
int m = 0;
for (int k=0; k<[arr count]; k++) {
    [[arrNew objectAtIndex:m]addObject:[arr objectAtIndex:k]];
    m++;
    if (m == numberofSubArrs) {
        m=0;
    }
}
int g=0;
int p=0;
while(p<[arr count]) {
    for (int z=0; z<[[arrNew objectAtIndex:g] count]; z++) {
        [[arrNew objectAtIndex:g] replaceObjectAtIndex:z withObject:[arr objectAtIndex:p++]];
    }
    g++;
}
NSLog(@"Required Array is:%@",[arrNew description]);
于 2012-11-20T12:40:49.513 回答
1

试试这个作为起点:

NSArray *array = [NSArray arrayWithObjects:@"a", @"b", @"c", @"d", @"e", @"f", @"g", @"h", nil];
NSMutableArray *manyArrays = [NSMutableArray array];
int numberOfElementsInSubArrays = 2;
int numberOfSubArrays = ceil((float)[array count] / (float)numberOfElementsInSubArrays);
for (int i = 0; i < numberOfSubArrays; i++) {
    NSMutableArray *subArray = [NSMutableArray array];
    for (int j = 0; j < numberOfElementsInSubArrays; j++) {
        if (i*numberOfElementsInSubArrays+j < [array count]) {
            NSLog(@"Array: %d Value:%@", i, [array objectAtIndex:i*numberOfElementsInSubArrays+j]);
            [subArray addObject:[array objectAtIndex:i*numberOfElementsInSubArrays+j]];
        }
    }
    [manyArrays addObject:subArray];
}
于 2012-11-20T12:38:47.870 回答
0

试试这个。

NSMutableArray *splitted = [NSMutableArray array];    
id firstItem, secondItem;
for (NSInteger i=0; i <= [originalArray count]-1; i+=2) {
        @try {
            firstItem = [originalArray objectAtIndex:i];
            secondItem = [originalArray objectAtIndex:i+1];
        }
        @catch (NSException *exception) {
            secondItem = [NSNull null];
        }
        @finally {
            [splitted addObject:@[firstItem,secondItem]];
        }
 }
于 2012-11-20T12:31:46.840 回答