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我的testPerfect方法有问题。我需要它来计算因子并将它们放入数组中，然后返回一个布尔值trueorfalse数字是否完美。到目前为止，该数组刚刚得到 1,2,3...5,6,7... 到输入要检查的任何数字。有什么建议么？

import java.util.Arrays;
import java.util.Scanner;

public class moo_Perfect
{
public static void main ( String args [] )
{
    int gN;
    int gP = getPerfect();
    int [] array = new int[100];
    boolean tP = testPerfect(gP, array);
    //int printFactors;
    System.out.println(Arrays.toString(array));
}


public static int getNum() //Get amount of numbers to check
{
Scanner input = new Scanner ( System.in );
System.out.print( "How many numbers would you like to test? " );
int count = input.nextInt();
int perfect = 1;
boolean vN = validateNum(count, perfect);
while(!vN)
{
    System.out.print (" How many numbers would you like to test? ");
    count = input.nextInt();
    vN = validateNum(count, perfect);
}
return count;
}   

public static boolean validateNum( int count, int perfect  ) //Check if number is valid
{
if (( count <= 0) || ( perfect <= 0))

{ 
    System.out.print( "Non-positive numbers are not allowed.\n");
}



else 
{
    return true;
}
return false;


}
public static int getPerfect() //Gets the numbers to test
{
Scanner input = new Scanner ( System.in );
int perfect = -1;
int count = getNum();
System.out.print("Please enter a perfect number: " );
perfect = input.nextInt();  
boolean vN = validateNum(perfect, count);
while (!vN) 
{
    System.out.print("Please enter a perfect number: ");
    perfect = input.nextInt();
    vN=validateNum(perfect, count);
}
return perfect;
}


public static boolean testPerfect( int perfect, int[] array )

{
//testPerfect(perfect, array);
int limit = perfect;
int index = 0;
for ( int i = 1; i <=limit; i++)
{
    array[index++] = i;
    perfect /= i;
}
array[index] = perfect;
int sum = 0;
for ( int i =0; i < array.length; i++)
{
    sum = sum + array[i];
}

if ( sum == perfect)
{
    int[] w = array;

    return true;        
}

else
{
    return false;
}


}
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1 回答 1

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这是 a 的工作List，而不是数组（因为您不知道数组应该有多长，List请注意这一点）。在实例化整数列表（例如factors）后，您可以将第一个for-loop 的主体更改为

if (perfect % i == 0) factors.add(i)

即“i仅当它平均分为perfect”时才添加到我们的因子列表中。

编辑：如果你必须使用一个数组，你可以这样做

array[i] = (perfect % i == 0) ? i : 0

i只有当它分开时，它才会放在你的数组中，perfect否则它会放置0。因此，该数组中的元素之和将等于 的因子之和perfect。

于 2012-11-20T01:42:25.433 回答