如果我的帐户 [MAX] 的 MAX 为 10，并且循环提示用户在帐户 [MAX] 中输入帐户#s，我该如何编写代码以查看帐户数量是否超过 10，并告诉用户已输入最大帐户数且不再接受输入？
这是我的 do while 循环
do
{
printf ("Options Available: \n");
printf ("\n 1 - Enter a transaction");
printf ("\n 2 - View the general journal");
printf ("\n 3 - View the balance sheet");
printf ("\n q - Quit the program\n");
printf ("\nPlease enter 1, 2, 3 or q: ");
option = validateoption();
if (option == '1')
{
printf ("\nEnter an account number (between 1000 and 3999): ");
accounts[i] = validateaccount();
printf ("\n");
printf ("Enter d (debit) or c (credit): ");
debcred[i] = validatedebcred();
printf ("\n");
printf ("Enter transaction amount: ");
amount[i] = validateamount();
printf ("\n");
printf ("\n");
i++;
totalinput++;
}
if (option == '2')
journal(accounts, debcred, amount, &totalinput);
if (option == '3')
balancesheet(accounts, debcred, amount, &totalinput);
} while (option != 'q');
如果您输入 1、2、3 或 q，就可以说它有效。现在在帐户[i] 中，如果帐户数超过 10，我可以写什么来告诉用户已输入最大帐户数并且不接受更多输入？
我的验证帐户功能：
long validateaccount() { // VALIDATE INPUT FOR ACCOUNT # IN TRANSACTION FUNCTION
int keeptrying = 1, rc;
long i;
char after;
do
{
rc = scanf ("%ld%c", &i, &after);
if (rc == 0)
{
printf (" **Invalid input try again: ");
clear();
}
else if (after != '\n')
{
printf (" **Trailing characters try again: ");
clear();
}
else if (i < 1000 || i > 3999)
{
printf (" **Invalid input try again: ");
}
else
{
keeptrying = 0;
}
} while (keeptrying == 1);
return i;
}