有一个简单的技巧可以将连续的条目折叠成一个组。如果按 (row_number - entry) 分组,则连续的条目将最终在同一组中。这是一个示例,说明我的意思:
查询:
SELECT phonenum, @curRow := @curRow + 1 AS row_number, phonenum - @curRow
from phonenums p
join (SELECT @curRow := 0) r
结果:
| PHONENUM | ROW_NUMBER | PHONENUM - @CURROW |
-------------------------------------------------
| 27100070000 | 1 | 27100069999 |
| 27100070001 | 2 | 27100069999 |
| 27100070002 | 3 | 27100069999 |
| 27100070003 | 4 | 27100069999 |
| 27100070004 | 5 | 27100069999 |
| 27100070005 | 6 | 27100069999 |
| 27100070008 | 7 | 27100070001 |
| 27100070009 | 8 | 27100070001 |
| 27100070012 | 9 | 27100070003 |
| 27100070015 | 10 | 27100070005 |
| 27100070016 | 11 | 27100070005 |
| 27100070040 | 12 | 27100070028 |
请注意连续的条目如何具有相同的值PHONENUM - @CURROW
。如果我们对该列进行分组,并选择每个组的最小值和最大值,您将获得摘要(有一个例外:如果需要,您可以将 END 值替换为NULL
if START = END):
查询:
select min(phonenum), max(phonenum) from
(
SELECT phonenum, @curRow := @curRow + 1 AS row_number
from phonenums p
join (SELECT @curRow := 0) r
) p
group by phonenum - row_number
结果:
| MIN(PHONENUM) | MAX(PHONENUM) |
---------------------------------
| 27100070000 | 27100070005 |
| 27100070008 | 27100070009 |
| 27100070012 | 27100070012 |
| 27100070015 | 27100070016 |
| 27100070040 | 27100070040 |
演示:http ://www.sqlfiddle.com/#!2/59b04/5