1

I want to create same structure of table in another table..

But it should create same table structure with all primary keys and indexes of that old table.

I tried below but it copies only columns.. not primary key nor indexes.

SELECT *
INTO dbo.NewTable
FROM dbo.ExistingTable
WHERE 1 = 2

How can I copy/clone that too?

4

1 回答 1

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我正在向您发布我用来创建数据库克隆的脚本的一部分，我删除了一些部分并且它缺少 FK 和索引（但是 PK 在那里，忽略身份：P）但应该给你一个提示你如何能做到这

当心：它没有经过优化，因为我需要运行它 1 次而不是按计划运行，我只是让它与我的数据库一起工作：P 根据您的需要修复它：

declare @DestinationSchema nvarchar(50) = 'frontier'
declare @SourceSchema nvarchar(50) = 'dbo'

select  so.name as TableName
        ,N'create table [' + @DestinationSchema + '].[' + so.name + '] (' + o.list + (case when kc.name IS NULL then '' else ' CONSTRAINT ' + kc.name  + ' PRIMARY KEY CLUSTERED ' + ' (' + LEFT(j.List, Len(j.List)-1) + '))' end) as TableScript
from    sys.objects so
cross apply
    (select 
        -- column name
        '  ['+cl.name+'] ' + 
        -- column type
        t.name + 
        -- type lenght
        (case t.name
            when 'sql_variant' then ''
            when 'text' then ''
            when 'ntext' then ''
            when 'bit' then '' 
            when 'int' then ''
            when 'tinyint' then ''
            when 'smallint' then ''
            when 'bigint' then ''
            when 'timestamp' then ''
            when 'date' then ''
            when 'smalldatetime' then ''
            when 'datetime' then ''
            when 'datetime2' then ''
            when 'real' then ''
            when 'float' then ''
            when 'time' then ''
            when 'decimal' then '(' + cast(cl.[precision] as varchar) + ', ' + cast(cl.scale as varchar) + ')'
            else '('+ (case when cl.max_length = -1 then 'MAX' else cast(cl.max_length as varchar) end) +')' end) + ' ' +
        -- nullable
        (case when cl.is_nullable = 0 then 'NOT ' else '' end ) + 'NULL,'
     from sys.columns cl
            inner join sys.types t on cl.user_type_id = t.user_type_id
     where object_id = so.object_id
     order by cl.column_id
    for xml path('')
    ) o (list)
inner join sys.schemas sch on so.[schema_id] = sch.[schema_id] AND sch.name = @SourceSchema
left join sys.key_constraints kc on so.[object_id] = kc.parent_object_id AND kc.[type] = 'PK' AND kc.[schema_id] = so.[schema_id]
cross apply
    (select N'[' + col.name + '], '
     from   sys.columns col 
                inner join sys.indexes i on col.[object_id] = i.[object_id] and i.is_primary_key = 1
                inner join sys.index_columns ic on ic.object_id = so.object_id and ic.column_id = col.column_id and ic.index_id = i.index_id
     where  col.[object_id] = so.[object_id]
     order by ic.key_ordinal
     for xml path('')) j (list)
cross apply
    (select N'[Destination].[' + col.name + '] = [Source].[' + col.name + '] AND '
     from   sys.columns col 
                inner join sys.indexes i on col.[object_id] = i.[object_id] and i.is_primary_key = 1
                inner join sys.index_columns ic on ic.object_id = so.object_id and ic.column_id = col.column_id and ic.index_id = i.index_id
     where  col.[object_id] = so.[object_id]
     order by ic.key_ordinal
     for xml path('')) k (list)     
where
    so.[type] = 'U'
order by
    so.name
于 2012-11-19T10:21:49.640 回答