0

我在这个程序的开始时遇到了一些麻烦。它应该取一个数字并确定它是否完美。目前我有它询问要检查多少个数字，每当我输入任何正数时，它都会再次询问。而且，每当我为第二个问题输入负数时，程序就会结束并且不再提示。有想法该怎么解决这个吗？

import java.util.Scanner;

public class aermel_Perfect
{
public static void main ( String args [] )
{
    int gN = getNum();
    int gP = getPerfect();
}


public static int getNum() //Get amount of numbers to check
{
Scanner input = new Scanner ( System.in );
System.out.print( "How many numbers would you like to test? " );
int count = input.nextInt();
int perfect = 1;
boolean vN = validateNum(count, perfect);
return count;
}   

public static boolean validateNum( int count, int perfect  ) //Check if number is valid
{
if (( count <= 0) || ( perfect <= 0))

{ 
    System.out.print( "Non-positive numbers are not allowed.\n");
}



else 
{
    return true;
}
return false;


}
public static int getPerfect() //Gets the numbers to test
{
Scanner input = new Scanner ( System.in );
int perfect = -1;
int count = getNum();
System.out.print("Please enter a perfect number: " );
perfect = input.nextInt();
boolean vN = validateNum(perfect, count);
return perfect;
}
}
4

2 回答 2

0 
int count = getNum();
System.out.print("Please enter a perfect number: " );
perfect = input.nextInt();

你在这里得到两个数字。

于 2012-11-19T05:40:52.647 回答
0

在您的方法中使用while循环，get例如重复要求输入，直到输入有效数字。

    public static int getNum() //Get amount of numbers to check
    {
      Scanner input = new Scanner ( System.in );
      System.out.print( "How many numbers would you like to test? " );
      int count = input.nextInt();
      int perfect = 1;
      boolean vN = validateNum(count, perfect);
      while(!vN ){
          System.out.println("Invalid input. Try again");
          count = input.nextInt();
          vN = validateNum(count, perfect);
      }
      return count;
    }

同样，更新方法并从此方法getPerfect中删除语句。int count = getNum();

编辑： 要反复要求完美的count次数，请更新您的主要方法，如下所示：

   public static void main ( String args [] )
   {
      int gN = getNum();
      for(int indx=0; indx <gN; indx++){
         int gP = getPerfect();
         //use your gP numbers in the way you want
      }
   }

EDIT1：要调用How many numbers would you like to test? "两次，我认为您可以getNum()在主方法中简单地调用您的方法两次，如下所示：

   public static void main ( String args [] )
   {
      int gN = getNum();//first call
      gN = getNum(); //second call
      int gP = getPerfect();
   }
于 2012-11-19T05:42:39.963 回答