python - Flask - 从函数中获取路由 URL

Question

@app.route('/this/is/the/url')
def some_exposed_func():
    return render_template("data.html")

如何从some_exposed_func句柄中获取“/this/is/the/url”？

print 'The func URL is: %s' % get_flask_route_url(some_exposed_func)

Answer 1

找到我自己：url_for()就是答案