我对编程很陌生,这是我第一次尝试使用 Python 创建复杂的脚本
我正在创建的程序的目的是:
- 浏览文件列表(单个文件夹中共有 360 个文件)
- 提取文件名中的 3 个唯一字符并根据 3 个字符创建一个文件夹(共 60 个唯一文件夹)
- 创建一个 for 循环,该循环遍历源文件夹中的文件列表并将其移动到相应的目标文件夹。
例子:
文件名:KPHI_SDUS81_N3KDIX_201205261956
基于字符创建的文件夹:N3K
import os
#Creates a list based on file names in the folder
srcfile=os.listdir("E:\\Learning Python\\Testing out\\thunderstorm stuff")
#Directiory of where the source files are located
srcpath= "E:\\Learning Python\\Testing out\\thunderstorm stuff"
#Creates a list based on the location of where folders will be lcoated.
#List will be empty since for loop has not ran yet
targetsrc=os.listdir("E:\\Learning Python\\Testing out\\test folder")
#path of where the new folders created will be located
targetpath = "E:\\Learning Python\\Testing out\\test folder"
#empty list created to hold a string of 3 characters (see for loop below)
list=[]
#A list to hold the unique string values. (see 2nd for loop below)
Target=[]
#the for loop below looks at a file and gooes to the character place holder index of 12 and looks at the characters UP TO 15.
#It then assigns the three characters to a variable x which then passes the the string (the 3 characters) to an empty list called list.
for num in srcfile:
x=num[12:15]
list.append(x)
#a test to see if the for loop above was able to exact the three characters from the list
print list
print srcfile
#created to see how big the list is which should match the amount of files in folder
print len(srcfile)
print len (list)
#a function created to make a folder based on a list
def create(s):
targetpath = "E:\\Learning Python\\Testing out\\test folder"
test=os.mkdir(os.path.join(targetpath,s))
#a dummy variable holder for the for loop below
valhold = "null"
#a nested if statement inside a for loop.
#The for loop goes through all the string values in a list called "list" (assigned to folder in for loop)
#and checks it against a list called valhold. If folder and valhold are not equal,
#the values in folder are appened to a list called Target.append which holds unique values.
#The next step is to create a folder a folder based off the list value "valhold"
for folder in list:
if folder != valhold:
Target.append(folder)
valhold=folder
create(valhold)
else:
valhold=folder
#a nested for loop which goes through all the files in the folder for the list "sourcefile"
#and finds a matching filename
for dst in Target:
wheretonumber=0
whereto = targetsrc(wheretonumber) #Name of folder for a given index value "targetsrc"
for file in list:
filenumber=0
filename=srcfile(filenumber) #Name of file for a given index value "sourcefile"
if file == dst:
##os.rename(filename(filenumber),whereto(wheretonumber))
##shutil.move(filename,whereto)
filenumber= filenumber+1
wheretonumber=wheretonumber+1
我能够完成上面的要点列表中的前 2 件事,但很难让第 3 件事发挥作用。我研究了 shutil.move、os.path.walk 和 os.rename 函数,但没有让它们正常工作。我不断收到错误:
whereto = targetsrc(wheretonumber) TypeError: 'list' object is not callable
我有 os.rename 和 shutil.move 注释掉,因为我正在尝试不同的功能。我的逻辑在方法中是正确的还是我错过了什么?关于尝试其他功能的任何建议或更改我的代码以使其将文件移动到文件夹中?