assembly - Recursive Fibonacci IA32 assembly

Question

I'm trying to solve a homework assignment - I managed to produce a working piece of code but it's producing the wrong answer. I tried debugging with gdb but I still can't see what's wrong with my code.

.data
        a : .long 6                                                                                                                                                             
        r : .long 0
        out : .string "result %d\n"
.text
.global main                                                                                                                                                                    
fib:
        pushl %ebp
        movl %esp, %ebp
        movl 8(%ebp), %eax
        cmpl $0, %eax #fib(0)=0
        je endf
        cmpl $1, %eax #fib(1)=1
        je endf
        decl %eax #eax=n-1
        movl %eax, %edx #edx=n-1
        pushl %edx  #save n-1
        pushl %eax #set arg
        call fib #re in ecx                                                                                                                                                     
        popl %eax #get n-1
        decl %eax #eax=n-2
        pushl %ecx #save result for n-1                                                                                                                                         
        pushl %eax #set arg
        call fib #res in ecx                                                                                                                                                    
        popl %eax # eax=fib(n-1)                                                                                                                                                
        addl %eax, %ecx #fib(n)=fib(n-1)+fib(n+2)                                                                                                                               
        movl %ebp,%esp #Exit                                                                                                                                                    
        popl %ebp
        ret
endf:
        movl %eax, %ecx#fib(0) or fib(1) to %ebx                                                                                                                                
        movl %ebp,%esp                                                                                                                                                          
        popl %ebp
        ret

main:
        pushl a  #stack [a]                                                                                                                                                     
        call fib #result in %ecx                                                                                                                                                
        pushl %ecx                                                                                                                                                              
        pushl $out                                                                                                                                                              
        call printf 

Answer 1

请注意，您不会删除传递给fib任何地方的任何参数，因此您的堆栈会变得不平衡。请参阅运行中的固定版本。

此外，典型的调用约定以eax. ecx无缘无故使用是令人困惑的。查看更好地遵守约定的简化版本。