c# - htmlagilitypack - 删除脚本和样式？

Question

我使用以下方法提取文本表单 html：

    public string getAllText(string _html)
    {
        string _allText = "";
        try
        {
            HtmlAgilityPack.HtmlDocument document = new HtmlAgilityPack.HtmlDocument();
            document.LoadHtml(_html);


            var root = document.DocumentNode;
            var sb = new StringBuilder();
            foreach (var node in root.DescendantNodesAndSelf())
            {
                if (!node.HasChildNodes)
                {
                    string text = node.InnerText;
                    if (!string.IsNullOrEmpty(text))
                        sb.AppendLine(text.Trim());
                }
            }

            _allText = sb.ToString();

        }
        catch (Exception)
        {
        }

        _allText = System.Web.HttpUtility.HtmlDecode(_allText);

        return _allText;
    }

问题是我也得到了脚本和样式标签。

我怎么能排除他们？

Answer 1

HtmlAgilityPack.HtmlDocument doc = new HtmlAgilityPack.HtmlDocument();
doc.LoadHtml(html);

doc.DocumentNode.Descendants()
                .Where(n => n.Name == "script" || n.Name == "style")
                .ToList()
                .ForEach(n => n.Remove());

Answer 2

HtmlDocument您可以使用类来做到这一点：

HtmlDocument doc = new HtmlDocument();

doc.LoadHtml(input);

doc.DocumentNode.SelectNodes("//style|//script").ToList().ForEach(n => n.Remove());

Answer 3

一些很好的答案，System.Linq 很方便！

对于非基于 Linq 的方法：

private HtmlAgilityPack.HtmlDocument RemoveScripts(HtmlAgilityPack.HtmlDocument webDocument)
{

// Get all Nodes: script
HtmlAgilityPack.HtmlNodeCollection Nodes = webDocument.DocumentNode.SelectNodes("//script");

// Make sure not Null:
if (Nodes == null)
    return webDocument;

// Remove all Nodes:
foreach (HtmlNode node in Nodes)
    node.Remove();

return webDocument;

}

Answer 4

public static string StripStyles(this string html)
{
    var document = new HtmlDocument();

    document.LoadHtml(html);

    foreach (var node in document.DocumentNode.DescendantsAndSelf())
    {
        var toRemove = node.Attributes.Where(x => x.Name == "style" || x.Name == "script")
            .ToList();
        foreach (var attribute in toRemove)
        {
            attribute.Remove();
        }
    }

    return document.DocumentNode.OuterHtml;
}