2

可能重复:
如何在 Oracle 中显示最高值的记录?

我应该显示数据库中最年长的人的姓名和年龄。我使用的代码显示了几个人的姓名和计算出的年龄,但它不会显示一个最年长的人。我怎样才能让它工作?这是我的代码

select dr_drvname as "Name", trunc(max((sysdate-dr_brthdate)/365)) as "Highest AGE"
from driver,dual
group by dr_drvname;
4

3 回答 3

2

Oracle 中的另一种方法是:

SELECT
    dr_drvname AS "Name",
    trunc(months_between(sysdate, dr_birthdate) / 12) AS "Highest Age"
FROM
(
SELECT
    dr_drvname,
    dr_birthdate
FROM
    driver
ORDER BY
    dr_birthdate
)
WHERE
    ROWNUM = 1;
于 2012-11-18T02:00:54.523 回答
1

尝试这样的事情:

SELECT top 1
  Firstname, LastName, Max([BirthDate]) as Oldest    
  FROM [Employees]
  group by BirthDate, FirstName, LastName

注意:如果多人有相同的出生日期,有什么要求?

于 2012-11-18T01:32:58.237 回答
1

您可以使用分析函数

select dr_drvname as "Name", 
       trunc( months_between( sysdate, dr_birthdate )/ 12 ) "Highest Age"
  from (select dr_drvname ,
               dr_birthdate,
               rank() over (order by dr_birthdate) rnk
          from driver)
 where rnk = 1;
于 2012-11-18T01:45:07.910 回答