1

在这段代码上,我得到了巨大的错误

static void ParseTheCommandLine(int argc, char *argv[])
{
int count;
int seqNumber;

namespace po = boost::program_options;

std::string appName = boost::filesystem::basename(argv[0]);

po::options_description desc("Generic options");
desc.add_options()
("version,v", "print version string")
("help", "produce help message")
("sequence-number", po::value<int>(&seqNumber)->default_value(0), "sequence number")
("pem-file", po::value< vector<string> >(), "pem file")
;

po::positional_options_description p;
p.add("pem-file", -1);

po::variables_map vm;
po::store(po::command_line_parser(argc, argv).
          options(desc).positional(p).run(), vm);
po::notify(vm);

if (vm.count("pem file"))
{
    cout << "Pem files are: "
         << vm["pem-file"].as< vector<string> >() << "\n";
}

cout << "Sequence number is " << seqNumber << "\n";

exit(1);

../../../FIXMarketDataCommandLineParameters/FIXMarketDataCommandLineParameters.hpp|98|错误:在 'std::operator<< [with _Traits = std::char_traits](((std:: basic_ostream >&)(& std::cout)), ((const char*)"Pem 文件为:")) << ((const boost::program_options::variable_value*)vm.boost::program_options::variables_map ::operator[](((const std::string&)(& std::basic_string, std::allocator >(((const char*)"pem-file"), ((const std::allocator&)(( const std::allocator*)(& std::allocator())))))))->boost::program_options::variable_value::as with T = std::vector, std::allocator >, std ::allocator, std::allocator > > >'|

4

1 回答 1

3

向量不实现ostream & operator<<(std::ostream &).

你可能应该这样做:

cout << "Pem files are: ";
for (auto & x : vm["pem-file"].as< vector<string> >())
    cout << x << "\n";
于 2012-11-17T16:55:48.293 回答