objective-c - 删除 NSString 中的特殊字符

Question

我正在将段落转换为包含许多特殊字符的单词，例如

"  , "  . `

如何删除 nsstring 中的这些字符并仅获取 nsstring 中的字母

前“新”到新//the special characters are change

Answer 1

NSString *unfilteredString = @"!@#$%^&*()_+|abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString:@"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"] invertedSet];
NSString *resultString = [[unfilteredString componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:@""];
NSLog (@"Result: %@", resultString);

试试这个它可以帮助你

Answer 2

有很多方法可以处理这个问题。例如，这是一个使用正则表达式的解决方案。这只是一个例子。我们不知道您要删除的所有特殊字符范围。

#import <Foundation/Foundation.h>

int main(int argc, const char * argv[])
{

    @autoreleasepool {
        NSRegularExpression *expression = [NSRegularExpression regularExpressionWithPattern:@"[,\\.`\"]"
                                                                                    options:0
                                                                                      error:NULL];
        NSString *sampleString = @"The \"new\" quick brown fox, who jumped over the lazy dog.";
        NSString *cleanedString = [expression stringByReplacingMatchesInString:sampleString
                                                                       options:0
                                                                         range:NSMakeRange(0, sampleString.length)
                                                                  withTemplate:@""];
        printf("cleaned = %s",[cleanedString UTF8String] );

    }
    return 0;
}

Answer 3

根据@Rostyslav Druzhchenko 对@MadhuP 所选答案的评论：

NSString *unfilteredString = @"!@#$%^&*()_+|abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
NSCharacterSet *notAllowedChars = [[NSCharacterSet alphanumericCharacterSet] invertedSet];
NSString *escapedString = [[unfilteredString componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:@""];
NSLog (@"Result: %@", escapedString);

这是alphanumericCharacterSet用于处理多个国家字符集的答案。

Answer 4

SWIFT 接受的答案（但不是 SWIFTY 方式）：

 let notAllowedCharactersSet = NSCharacterSet(charactersInString: "ABCDEFGHIJKLMNOPQRSTUVWXYZ").invertedSet
 let filtered = (stringToFilter.componentsSeparatedByCharactersInSet(notAllowedCharactersSet) as NSArray).componentsJoinedByString("")

Answer 5

我确信有一个更优雅的解决方案，但对于任何试图在 Swift 中执行此操作的人，我都会这样做以确保我的用户电话号码中没有特殊字符。

var phone = "+1 (555) 555 - 5555"
var removeChars: NSCharacterSet = NSCharacterSet(charactersInString: "1234567890").invertedSet
var charArray = phone.componentsSeparatedByCharactersInSet(removeChars)
var placeholderString = ""
var formattedPhoneNumber: String = placeholderString.join(charArray).stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())

stringByTrimmingCharactersInSet可能没有必要。