sql - Rails：按第二个子属性过滤模型

Question

我似乎无法弄清楚这一点。如果它深入一层，我可以做到。（使用类似的东西A.joins(:bs).where("bs.paid = TRUE")）

但我有一个模型 A has_many B。B has_one C. 终于C有了一个属性paid。

我想得到所有A的地方C.paid == true。

我正在寻找类似的东西A.joins({:b, :c}).where("c.paid == True")

Answer 1

Something like this?

A.joins(:b, :c).where(:conditions => ["c.paid = ?", true])

Found here, take a look it might interest you: "11.2.2 Joining Multiple Associations" http://guides.rubyonrails.org/active_record_querying.html

Answer 2

paid_items = Array.new

A.bs.each do |b_item|
  paid_items << b_item if b_item.c.paid
end