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  • jQuery 1.7.2
  • jQuery 验证 1.1.0
  • jQuery 表单 3.18
  • WordPress 3.4.2

我正在尝试在上面的环境中/使用上面的 jQuery 库编写联系人/邮件表单。现在我遇到了 jQuery Form JS 的问题:

我已经从开发人员页面获取了原始代码,ajaxSubmit并且仅将目标选项更改为我的 HTML 源代码中存在的 ID,并$在 function 中替换为 jQuery showRequest

问题是,以命名的函数success:不会触发。我尝试了同样的方法error:,但又没有被解雇。

只做complete:了,我放在那里的功能responseText从接收脚本发出警报。

有谁知道出了什么问题?

代码:

jQuery(document).ready(function() {
var options = { 
    target:        '#mail-status',   // target element(s) to be updated with server response 
    beforeSubmit:  showRequest,  // pre-submit callback 
    success:       showResponse,  // post-submit callback 

    // other available options: 
    //url:       url         // override for form's 'action' attribute 
    //type:      type        // 'get' or 'post', override for form's 'method' attribute 
    //dataType:  null        // 'xml', 'script', or 'json' (expected server response type) 
    //clearForm: true        // clear all form fields after successful submit 
    //resetForm: true        // reset the form after successful submit 

    // $.ajax options can be used here too, for example: 
    //timeout:   3000 
};
jQuery("#mailform").validate(
{
    submitHandler: function(form)   { jQuery(form).ajaxSubmit(options); },
    errorPlacement: function(error, element) { },
    rules: {
        author: {
            minlength: 2,
            required: true
        },
        email: {
            required: true,
            email: true
        },
        comment: {
            minlength: 2,
            required: true
        }
    },
    highlight: function(element) 
    {
        jQuery(element).addClass("e");
        jQuery(element.form).find("label[for=" + element.id + "]").addClass("e");
    },
    unhighlight: function(element) 
    {
        jQuery(element).removeClass("e");
        jQuery(element.form).find("label[for=" + element.id + "]").removeClass("e");
    }
});
});
// pre-submit callback 
function showRequest(formData, jqForm, options) { 
// formData is an array; here we use $.param to convert it to a string to display it 
// but the form plugin does this for you automatically when it submits the data 
var queryString = jQuery.param(formData); 

// jqForm is a jQuery object encapsulating the form element.  To access the 
// DOM element for the form do this: 
// var formElement = jqForm[0]; 

alert('About to submit: \n\n' + queryString); 

// here we could return false to prevent the form from being submitted; 
// returning anything other than false will allow the form submit to continue 
return true; 
} 
// post-submit callback 
function showResponse(responseText, statusText, xhr, $form)  { 
// for normal html responses, the first argument to the success callback 
// is the XMLHttpRequest object's responseText property 

// if the ajaxSubmit method was passed an Options Object with the dataType 
// property set to 'xml' then the first argument to the success callback 
// is the XMLHttpRequest object's responseXML property 

// if the ajaxSubmit method was passed an Options Object with the dataType 
// property set to 'json' then the first argument to the success callback 
// is the json data object returned by the server 

alert('status: ' + statusText + '\n\nresponseText: \n' + responseText + 
    '\n\nThe output div should have already been updated with the responseText.'); 
} 
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2 回答 2

0

查看验证是否成功并被jQuery(form).ajaxSubmit(options);调用。

于 2012-11-16T10:57:36.573 回答
0

这是原始提问者作为编辑添加的,我已将其转换为社区 wiki 答案,因为它应该是答案,而不是编辑。

找到原因/错误。这是由我将 jquery.form.js 排队的方式引起的,我将其存储在主题的子目录中。

我将“jquery-form”作为 wp_enqueue_script 中的句柄传递。“jquery-form”已由 WP 分配并连接到包含 jquery.form.js 的 WP。包含的版本(2.x)不支持我通过的选项。

我必须取消注册分配的脚本并将句柄注册到存储在我的主题中的当前 jquery.form.js。

于 2015-06-22T19:49:17.193 回答