所以我有点卡在这里，我可以用 foreach 循环来做，但我想找到一种更聪明的方法。
更新：我在问题中遗漏了一些东西。数组可能以随机顺序和不同长度出现，因此具有不同的密钥。以下示例已更新。
情况如下：
阵列1
array (
slug1 => England,
slug2 => France,
slug3 => Italy,
slug4 => Germany,
)
数组2
array (
slug2 => 215,
slug1 => 168,
slug4 => 55,
slug5 => 149,
slug3 => 40,
slug6 => 137,
)
我想与这些数组相交并构建具有以下元素的新数组：
array (
168 => England,
215 => France,
40 => Italy,
55 => Germany,
)
注意：元素没有排序，尽管这很容易实现。
回答原始问题
您可以使用array_combine它创建一个数组，将一个数组用作键，另一个数组用作其值
$array1 = array(
"slug1" => "England",
"slug2" => "France",
"slug3" => "Italy",
"slug4" => "Germany");
$array2 = array(
"slug1" => "168",
"slug2" => "215",
"slug3" => "40",
"slug4" => "55");
$final = array_combine($array2, $array1);
echo "<pre>";
print_r($final);
输出
Array
(
[168] => England
[215] => France
[40] => Italy
[55] => Germany
)
回答更新的问题
Update: There was something that I've missed in the question. The arrays may come in random order and in different length thus having different keys. Examples below updated.
$array1 = array(
"slug1" => "England",
"slug2" => "France",
"slug3" => "Italy",
"slug4" => "Germany");
$array2 = array (
"slug2" => 215,
"slug1" => 168,
"slug4" => 55,
"slug5" => 149,
"slug3" => 40,
"slug6" => 137);
$final = customCombine($array2, $array1);
echo "<pre>";
print_r($final);
输出
Array
(
[215] => France
[168] => England
[55] => Germany
[40] => Italy
)
使用的功能
function customCombine($keys, $arr) {
$t = array();
foreach ( $keys as $k => $val ) {
isset($arr[$k]) and $t[$val] = $arr[$k];
}
return $t;
}
Baba 的回答应该适合您，但这是一种处理数组和/或不同大小之间的不同键顺序的有趣方法。
// get values from $array2 in the order in which they appear in $array1
// whereby the array keys are used to match them
$keys = array_intersect_key($array2, $array1);
// create a new array with the keys found in the previous step and
// another array_intersect_key() to only select the matching items
// from $array1
array_combine($keys, array_intersect_key($array1, $keys));
它还确保array_combine()适用于相同大小的数组；的大小$array2是输出大小。
为了扩展Jack的答案，因为它可能会按照它们的构造顺序组合数组，而不是键匹配的顺序：
Array
(
[215] => England
[168] => France
[55] => Italy
[40] => Germany
)
一些中间数据杂耍可以将其整理出来（无论哪个数组更短，它都可以工作）：
$array1 = array(
'slug1' => 'England',
'slug2' => 'France',
'slug3' => 'Italy',
'slug4' => 'Germany'
);
$array2 = array (
'slug2' => 215,
'slug1' => 168,
'slug4' => 55,
'slug5' => 149,
'slug3' => 40,
'slug6' => 137
);
$keys = array_intersect_key($array2, $array1);
ksort($keys);
$intersect = array_intersect_key($array1, $keys);
ksort($intersect);
$final = array_combine($keys, $intersect);
print_r($final);
输出
Array
(
[168] => England
[215] => France
[40] => Italy
[55] => Germany
)
我找到了最适合我的解决方案：
<?php
$array1 = array("slug1" => "England","slug2" => "France","slug3" => "Italy","slug4" => "Germany");
$array2 = array("slug1" => "168","slug2" => "215","slug3" => "40","slug4" => "55", "slug5" => "178");
ksort($array1);
ksort($array2);
$test1 = array_intersect_key($array1, $array2);
$test2 = array_intersect_key($array2, $array1);
$final = array_combine($test2, $test1);
print_r($final);
?>
利用array_combine()
<?php
$a = array('green', 'red', 'yellow');
$b = array('avocado', 'apple', 'banana');
$c = array_combine($a, $b);
print_r($c);
?>