我有一个活动,它是一个单任务:
public class MyActivity extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
System.out.printf("### MyAcitvity.onCreate: " + getIntent().getExtras());
}
@Override
protected void onResume() {
super.onResume();
System.out.println("### MyActivity.onResume: " + getIntent().getExtras());
}
public void toNext(View v) {
startActivity(new Intent(this, AaaActivity.class));
}
}
和:
<activity android:name=".MyActivity" android:launchMode="singleTask" />
不,它已经启动,它启动了另一个名为AaaActivity
.
public class AaaActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.aaa);
}
public void jumpToFirst(View v) {
Intent intent = new Intent(this, MyActivity.class);
intent.putExtra("aaa","bbb");
startActivity(intent);
}
}
在后一个中,有一个按钮将触发jumpToFirst
方法启动第一个,并传递一个数据对aaa=bbb
。由于MyActivity
is singleTask
,它不会创建一个新实例,而是会返回到现有MyActivity
实例。
我的问题是:如何从AaaActivity
in获取传递的额外数据MyActivity
?
你可以看到我已经记录onCreate
和onResume
方法,但它打印空额外数据。
11-16 08:44:17.833: INFO/System.out(5171): ### MyAcitvity.onCreate: null
11-16 08:44:19.417: INFO/System.out(5171): ### MyActivity.onResume: null
11-16 08:44:26.041: INFO/System.out(5171): ### MyActivity.onResume: null
11-16 08:44:28.897: INFO/System.out(5171): ### MyActivity.onResume: null