5

我想通过我的 Android 4.03 设备使用 Ksoap2 连接到基于 dot.net 的 Web 服务。

我的问题是当我调用肥皂请求时，我得到了这个异常：

11-16 08:35:08.649: W/System.err(6392): java.lang.IllegalArgumentException: size <= 0
11-16 08:35:08.649: W/System.err(6392): at java.io.BufferedInputStream.<init>(BufferedInputStream.java:94)
11-16 08:35:08.649: W/System.err(6392): at org.ksoap2.transport.HttpTransportSE.call(HttpTransportSE.java:226)
11-16 08:35:08.649: W/System.err(6392):     at org.ksoap2.transport.HttpTransportSE.call(HttpTransportSE.java:114)
11-16 08:35:08.649: W/System.err(6392):     at at.jesenko.eDoc.MainActivity$1.run(MainActivity.java:48)

我正在使用的代码

    final String url = "http://server:9007/DWService?wsdl";
    final String NAMESPACE = "http://tempuri.org/";
    final String METHOD_NAME ="Login";
    final String SOAP_ACTION="http://tempuri.org/Login";

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    Thread loginThread = new Thread(){

            @Override
            public void run() {

                try {


                    SoapObject Request = new SoapObject(NAMESPACE, METHOD_NAME);
                    Request.addProperty("userName", "demo");
                    Request.addProperty("password", "demo1234");
                    Request.addProperty("organization", "Peters Engineering");

                    SoapSerializationEnvelope Envelope = new SoapSerializationEnvelope(
                            SoapEnvelope.VER12); 
                    Envelope.dotNet=true;
                    Envelope.setOutputSoapObject(Request);


                    HttpTransportSE ht = new HttpTransportSE(url);
                    ht.debug = true;
                    ht.call(SOAP_ACTION, Envelope);

                    SoapObject response = (SoapObject) Envelope.getResponse();
                    final String SessionID = response.getProperty("SessionID").toString();


                runOnUiThread(new Runnable() {

                    public void run() {

                        TextView tv = (TextView) findViewById(R.id.textView1);
                        tv.setText(SessionID);

                    }
                });

                } catch (Exception e) {

                    e.printStackTrace();

                }   

            }


    };
    loginThread.start();
}

这是我要调用的 wsdl 文件的一部分：

<wsdl:definitions name="DWService" targetNamespace="http://tempuri.org/">
 <wsdl:types>
  <xsd:schema elementFormDefault="qualified" targetNamespace="http://tempuri.org/">
   <xsd:element name="Login">
    <xsd:complexType>
     <xsd:sequence>
      <xsd:element minOccurs="0" name="userName" nillable="true" type="xsd:string"/> 
      <xsd:element minOccurs="0" name="password" nillable="true" type="xsd:string"/>
      <xsd:element minOccurs="0" name="organization" nillable="true" type="xsd:string"/> 
     </xsd:sequence>
    </xsd:complexType>
   </xsd:element>

我对 Ksoap 和 Web 服务没有太多经验，所以我希望有人可以帮助我解决这个问题 :)

问候。

编辑

我尝试改用 ?svc -> 相同的错误:(

编辑

这里 WSDL 文件的标题可能我的命名空间是错误的

    <?xml version="1.0" encoding="UTF-8"?>
    -<wsdl:definitions xmlns:wsam="http://www.w3.org/2007/05/addressing/metadata" xmlns:wsx="http://schemas.xmlsoap.org/ws/2004/09/mex" 
xmlns:wsa10="http://www.w3.org/2005/08/addressing" 
xmlns:msc="http://schemas.microsoft.com/ws/2005/12/wsdl/contract" xmlns:wsaw="http://www.w3.org/2006/05/addressing/wsdl" xmlns:wsap="http://schemas.xmlsoap.org/ws/2004/08/addressing/policy" xmlns:wsp="http://schemas.xmlsoap.org/ws/2004/09/policy" xmlns:wsa="http://schemas.xmlsoap.org/ws/2004/08/addressing" xmlns:tns="http://tempuri.org/" 
xmlns:soap12="http://schemas.xmlsoap.org/wsdl/soap12/" 
xmlns:xsd="http://www.w3.org/2001/XMLSchema" 
xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" 
xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" 
xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" 
targetNamespace="http://tempuri.org/" name="DWService">
-<wsdl:types>-
<xsd:schema targetNamespace="http://tempuri.org/" elementFormDefault="qualified">-
<xsd:element name="Login">-
<xsd:complexType>-
<xsd:sequence>
<xsd:element name="userName" type="xsd:string" nillable="true" minOccurs="0"/>
<xsd:element name="password" type="xsd:string" nillable="true" minOccurs="0"/>
<xsd:element name="organization" type="xsd:string" nillable="true" minOccurs="0"/></xsd:sequence>
</xsd:complexType>
</xsd:element>
-<xsd:element name="LoginResponse">
-<xsd:complexType>-
<xsd:sequence>
<xsd:element name="LoginResult" type="q1:ClientServiceSession" nillable="true" minOccurs="0" 
xmlns:q1="http://schemas.datacontract.org/2004/07/DocuWare.WebServices.GAPIFunctionality.DataContracts"/>
</xsd:sequence></xsd:complexType></xsd:element>

和肥皂部分：

-<wsdl:binding name="BasicHttpBinding_IDWService" type="tns:IDWService">
<soap:binding transport="http://schemas.xmlsoap.org/soap/http"/>
-<wsdl:operation name="Login"><soap:operation style="document" soapAction="http://tempuri.org/IDWService/Login"/>
-<wsdl:input><soap:body use="literal"/></wsdl:input>
-<wsdl:output><soap:body use="literal"/></wsdl:output></wsdl:operation>
-<wsdl:operation name="Logoff"><soap:operation style="document" soapAction="http://tempuri.org/IDWService/Logoff"/>
-<wsdl:input><soap:body use="literal"/></wsdl:input>
-<wsdl:output><soap:body use="literal"/></wsdl:output></wsdl:operation>

-<wsdl:service name="DWService">
-<wsdl:port name="BasicHttpBinding_IDWService" binding="tns:BasicHttpBinding_IDWService"><soap:address location="http://localhost:9007/DWService"/></wsdl:port></wsdl:service>

希望你能帮我 ;）

4

4 回答 4

2

用于Fiddler跟踪流量。可能服务器/服务正在返回Content-Length: 0 这可能是任何东西，在我的情况下，它是Content-type从客户端应用程序发送的不匹配和服务器端的预期内容类型。由于异常清楚地表明从ByteArrayInputStream服务接收到的长度 <= 0的内容。

我希望这会让您进行更多调查。

干杯，

于 2012-11-21T00:47:22.487 回答
1

像这样使用：

基本的Http绑定：

                SoapObject Request = new SoapObject(NAMESPACE, METHOD_NAME);
                Request.addProperty("userName", "demo");
                Request.addProperty("password", "demo1234");
                Request.addProperty("organization", "Peters Engineering");

                SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
                envelope.dotNet=true;
                envelope.setOutputSoapObject(Request);

                HttpTransportSE ht = new HttpTransportSE(URL);

               try {
                    ht.call(SOAP_ACTION, envelope);  
            final  SoapPrimitive response = (SoapPrimitive)envelope.getResponse();

我对您的代码进行了一些更改。

1)

SoapSerializationEnvelope 信封 = 新 SoapSerializationEnvelope(SoapEnvelope.VER12);

变成

SoapSerializationEnvelope 信封 = 新 SoapSerializationEnvelope(SoapEnvelope.VER11);

2） 我已从您的代码中删除了这部分。

ht.debug = true;

3)

SoapObject response = (SoapObject) Envelope.getResponse();

变成

SoapPrimitive 响应 = (SoapPrimitive)envelope.getResponse();

确保您在清单中添加了互联网权限

        <uses-permission android:name="android.permission.INTERNET"/>

如果你没有通过使用这个得到输出，问题可能是你的wsdl

更多参考 希望这会对你有所帮助。

PS。

WsHttpBinding：

     Element e = new Element();
    e.setName("To");
    e.setNamespace("http://www.w3.org/2005/08/addressing");
    e.addChild(Node.TEXT,
            "your URL HERE");


    Element e1 = new Element();
    e1.setName("Action");
    e1.setNamespace("http://www.w3.org/2005/08/addressing");
    e1.addChild(Node.TEXT,
            "http://tempuri.org/IService1/HelloTest");

request.addProperty("Celsius", "32");    

// use VER12 instead of VER11
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER12);

envelope.dotNet=true;

// add HederOut to envelope
envelope.headerOut = new Element[] { e, e1 };

envelope.setOutputSoapObject(request);

参考。

于 2013-08-02T06:26:32.740 回答
1

您是否在此行之后检查了调试？

SoapObject response = (SoapObject) Envelope.getResponse();

如果您已通过 web 服务返回属性？可能没有返回数据

利用

int arraySize = response.getPropertyCount();

并检查长度以了解您是否正在接收数据

我认为可以产生argumentException，因为您试图访问该属性而不在这里检查它：

final String SessionID = response.getProperty("SessionID").toString();

测试 propertyCount 并告诉我们。

编辑：

请对此进行测试：

将 SoapEnvelope 从 VER12 更改为 VER11

 SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                SoapEnvelope.VER11);

将 webService URL 从 wdsl 更改为此类型 (svc)：

 String URL = "http://host:8080/HelloWCF/Service1.svc";
于 2012-11-16T09:41:21.507 回答
-3

我的选择：1.使用最新的 3.1.0 ksoap2 jar：http ://code.google.com/p/ksoap2-android/wiki/HowToUse ?tm=2 2.将 v12 更改为 v11

于 2013-11-14T04:57:17.797 回答