我正在使用 Python 元素树来解析 xml 文件
假设我有一个这样的 xml 文件..
<html>
<head>
<title>Example page</title>
</head>
<body>
<p>hello this is first paragraph </p>
<p> hello this is second paragraph</p>
</body>
</html>
有什么方法可以提取带有完整 p 标签的身体，例如
desired= "<p>hello this is first paragraph </p> <p> hello this is second paragraph</p>"
以下代码可以解决问题。
import xml.etree.ElementTree as ET
root = ET.fromstring(doc) # doc is a string containing the example file
body = root.find('body')
desired = ' '.join([ET.tostring(c).strip() for c in body.getchildren()])
现在：
>>> desired
'<p>hello this is first paragraph </p> <p> hello this is second paragraph</p>'
你可以使用lxml库，lxml
因此，此代码将对您有所帮助。
import lxml.html
htmltree = lxml.html.parse('''
<html>
<head>
<title>Example page</title>
</head>
<body>
<p>hello this is first paragraph </p>
<p> hello this is second paragraph</p>
</body>
</html>''')
p_tags = htmltree.xpath('//p')
p_content = [p.text_content() for p in p_tags]
print p_content
与@DavidAlber 略有不同的方式，可以轻松选择孩子：
from xml.etree import ElementTree
tree = ElementTree.parse("example.xml")
body = tree.findall("/body/p")
result = []
for elem in body:
result.append(ElementTree.tostring(elem).strip())
print " ".join(result)