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蒙古菜鸟在这里。

好的，我收集了总共 30000 个（大约）的拉链。

他们看起来像这样......

{ "city" : "EPES", "loc" : [ -88.161443, 32.763371 ], "pop" : 1391, "state" : "AL", "_id" : "35460" }
{ "city" : "ETHELSVILLE", "loc" : [ -88.221987, 33.386816 ], "pop" : 719, "state" : "AL", "_id" : "35461" }
{ "city" : "EUTAW", "loc" : [ -87.930297, 32.888871 ], "pop" : 6586, "state" : "AL", "_id" : "35462" }
{ "city" : "FOSTERS", "loc" : [ -87.735688, 33.135859 ], "pop" : 2100, "state" : "AL", "_id" : "35463" }
{ "city" : "GAINESVILLE", "loc" : [ -88.271558, 32.908364 ], "pop" : 1051, "state" : "AL", "_id" : "35464" }
{ "city" : "GORDO", "loc" : [ -87.900504, 33.346917 ], "pop" : 4333, "state" : "AL", "_id" : "35466" }
{ "city" : "KNOXVILLE", "loc" : [ -87.791855, 32.982423 ], "pop" : 373, "state" : "AL", "_id" : "35469" }
{ "city" : "COATOPA", "loc" : [ -88.173592, 32.588509 ], "pop" : 6055, "state" : "AL", "_id" : "35470" }
{ "city" : "CYPRESS", "loc" : [ -87.615134, 32.978853 ], "pop" : 2659, "state" : "AL", "_id" : "35474" }
{ "city" : "NORTHPORT", "loc" : [ -87.591441, 33.283425 ], "pop" : 20114, "state" : "AL", "_id" : "35476" }

我需要使用聚合找到其中邮政编码最多的第四个州......我不知道。

任何帮助表示赞赏

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2 回答 2

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解决方案： 

db.zips.aggregate([ {$group:{_id:{state:"$state"},numberOfzipcodes:{$sum:1}}}, {$sort:{numberOfzipcodes:-1}}, {$limit:4}])
于 2012-11-15T21:33:50.243 回答
2

//按州分组，然后找到每个州的邮政编码总数，按邮政编码总数降序排序。然后使用skip跳过前3个状态并限制为1

db.zips.aggregate([{$group:{_id:{state:"$state"},zips:{$sum:1}}}, {$sort:{zips:-1}}, {$skip: 3}, {$limit:1}])

于 2013-05-16T07:46:58.017 回答