5

我找到了这个https://gist.github.com/2945472但我需要一个不依赖于 c++11 的实现。我尝试将其转换为仅使用 boost，但我遇到了一些麻烦。

这是我想出的：

#include <boost/any.hpp>
#include <boost/function.hpp>
#include <boost/bind.hpp>
#include <boost/lambda/lambda.hpp>
#include <boost/unordered_map.hpp>

struct type_info_hash {
    std::size_t operator()(std::type_info const & t) const {
        return t.hash_code();
    }
};

struct equal_ref {
    template <typename T> bool operator()(boost::reference_wrapper<T> a,boost::reference_wrapper<T> b) const {
        return a.get() == b.get();
    }
};
struct any_visitor {
    boost::unordered_map<boost::reference_wrapper<std::type_info const>, boost::function<void(boost::any&)>, type_info_hash, equal_ref> fs;

    template <typename T> void insert_visitor(boost::function<void(T)> f) {
        try {
            fs.insert(std::make_pair(boost::ref(typeid(T)), boost::bind(f, boost::any_cast<T>(boost::lambda::_1))));
        } catch (boost::bad_any_cast& e) {
            std::cout << e.what() << std::endl;
        }
    }

    bool operator()(boost::any & x) {
        boost::unordered_map<boost::reference_wrapper<std::type_info const>, boost::function<void(boost::any&)>, type_info_hash, equal_ref>::iterator it = fs.find(boost::ref(x.type()));
        if (it != fs.end()) {
            it->second(x);
            return true;
        } else {
            return false;
        }
    }
};

struct abc {};

void fa(int i) { std::cout << "fa(" << i << ")" << std::endl; }
void fb(abc) { std::cout << "fb(abc())" << std::endl; }

int main() {
    any_visitor f;
    f.insert_visitor<int>(fa);
    f.insert_visitor<abc>(fb);

    std::vector<boost::any> xs;
    xs.push_back(1);
    xs.push_back(abc());
    xs.push_back(1.5);

    for (auto & x : xs) {
        if (!f(x)) std::cout << "no visitor registered" << std::endl;
    }
}

插入地图时，我得到了 bad_any_cast。不应该 any_cast 仅由 it->second(x) 调用吗？我究竟做错了什么？

4

2 回答 2

3

您不能强制_1转换为T（在绑定表达式时）。

你需要一个懒惰的演员。也许定义一个函数并使用嵌套的绑定表达式，或者将 Boost Phoenix 与自定义any_cast角色一起使用。

这是嵌套绑定方法：

#include <boost/any.hpp>
#include <boost/function.hpp>
#include <boost/bind.hpp>
#include <boost/lambda/lambda.hpp>
#include <boost/unordered_map.hpp>

struct type_info_hash {
    std::size_t operator()(std::type_info const & t) const {
        return 42; // t.hash_code();
    }
};

struct equal_ref {
    template <typename T> bool operator()(boost::reference_wrapper<T> a,boost::reference_wrapper<T> b) const {
        return a.get() == b.get();
    }
};
struct any_visitor {
    boost::unordered_map<boost::reference_wrapper<std::type_info const>, boost::function<void(boost::any&)>, type_info_hash, equal_ref> fs;

    template <typename T> static T any_cast_f(boost::any& any) { return boost::any_cast<T>(any); }

    template <typename T> void insert_visitor(boost::function<void(T)> f) {
        try {
            fs.insert(std::make_pair(boost::ref(typeid(T)), boost::bind(f, boost::bind(any_cast_f<T>, boost::lambda::_1))));
        } catch (boost::bad_any_cast& e) {
            std::cout << e.what() << std::endl;
        }
    }

    bool operator()(boost::any & x) {
        boost::unordered_map<boost::reference_wrapper<std::type_info const>, boost::function<void(boost::any&)>, type_info_hash, equal_ref>::iterator it = fs.find(boost::ref(x.type()));
        if (it != fs.end()) {
            it->second(x);
            return true;
        } else {
            return false;
        }
    }
};

struct abc {};

void fa(int i) { std::cout << "fa(" << i << ")" << std::endl; }
void fb(abc) { std::cout << "fb(abc())" << std::endl; }

int main() {
    any_visitor f;
    f.insert_visitor<int>(fa);
    f.insert_visitor<abc>(fb);

    std::vector<boost::any> xs;
    xs.push_back(1);
    xs.push_back(abc());
    xs.push_back(1.5);

    for (auto it=xs.begin(); it!=xs.end(); ++it)
        if (!f(*it)) std::cout << "no visitor registered" << std::endl;
}

打印输出：

fa(1)
fb(abc())
no visitor registered
于 2012-11-15T14:06:22.883 回答
1

尝试使用可扩展的任何 https://sourceforge.net/projects/extendableany/?source=directory。

struct f_method
{
    typedef void (boost::mpl::_1::* signature) () const;

    template <typename T>
    struct wrapper
        : public T
    {
        void f() const
        {
            return this->call(f_method());
        }
    };

    struct implementation
    {
        void operator() (int i) const
        {
           std::cout << "fa(" << i << ")" << std::endl;
        }

        void operator() (abc) const
        {
           std::cout << "fb(abc())" << std::endl;
        }

        template <typename T>
        void operator() (const T& t) const
        {
            std::cout << "Errr" << std::endl;
        }
    };
};

typedef xany<boost::mpl::list<f_method> > any;

int main() {
    std::vector<any> xs;
    xs.push_back(1);
    xs.push_back(abc());
    xs.push_back(1.5);

    for (auto it=xs.begin(); it!=xs.end(); ++it)
        (*it).f();
}
于 2012-12-17T11:43:34.953 回答