您好,我正在为我的项目使用jQuery AS3 网络摄像头插件。但可以弄清楚如何获取拍摄的照片并将其添加到上传表单字段(如果可能的话)。当我单击捕获按钮时,它会在捕获窗口中显示图片,但实际上如何保存呢?
$("#webcam").webcam({
swffile: "js/sAS3Cam.swf?v=20120613",
previewWidth: 400,
previewHeight: 300,
resolutionWidth: 400,
resolutionHeight: 300,
noCameraFound: function () {
this.debug('error', 'Kamera negalima');
},
swfApiFail: function(e) {
this.debug('error', 'Įskiepio klaida');
},
cameraDisabled: function () {
this.debug('error', 'Prašom suteikti leidimą prisijungti kamrai prie puslapio');
},
debug: function(type, string) {
if (type == 'error') {
alert(string);
}
},
cameraEnabled: function () {
this.debug('notice', 'Camera enabled');
var cameraApi = this;
if (cameraApi.isCameraEnabled) {
return;
} else {
cameraApi.isCameraEnabled = true;
}
setTimeout(function() {
$(".capture").slideDown('fast');
}, 750);
$('.capture_btn').click(function() {
$(".capture").slideUp('fast');
$(".save_img").slideDown('fast');
var result = cameraApi.save();
if (result && result.length) {
var actualShotResolution = cameraApi.getResolution();
$('.reload_camera').click(function() {
cameraApi.isCameraEnabled = true;
});
} else {
cameraApi.debug('error', 'Bloga kamera');
}
});
}
});
<form action="processupload.php" style="display: none" method="post" enctype="multipart/form-data" id="UploadForm">
<table width="500" border="0">
<tr>
<td><input name="ImageFile" id="file" type="file" /></td>
</tr>
<tr>
<td style="display: none;"><input type="submit" id="SubmitButton" value="Upload" /></td>
</tr>
</table>
</form>