// The original code is from link: http://hoeven.blogbus.com/logs/37324287.html
#include<iostream>
#include<vector>
#include <stdlib.h>
using namespace std;
class test{
public:
int v;
/*构造函数*/
test():v(0){}
test(const int &a):v(a){}
test(const test &t1):v(t1.v){}
/*以下重载小于号 < */
//比较两个对象的大小
bool operator<(const test &t1) const{
return (v < t1.v);
}
//比较对象和int的大小
bool operator<(const int &t1) const{
return (v < t1);
}
//友元函数,比较int和对象的大小
friend inline bool operator<(const int &a, const test & t1){
return (a < t1.v);
}
/*以下重载赋值号 = */
//对象间赋值
test & operator=(const test &t1){
v = t1.v;
return *this;
}
//int赋值给对象
test & operator=(const int &t1){
v = t1;
return *this;
}
/*以下重载加号 + */
//对象加上 int
test operator+(const int & a){
test t1;
t1.v = v + a;
return t1;
}
//对象加对象
test operator+(test &t1){
test t2;
t2.v = v + t1.v;
return t2;
}
/*以下重载加等号 += */
//对象加上对象
test &operator+=(const test &t1){
v += t1.v;
return *this;
}
//对象加上int
test &operator+=(const int &a){
v += a;
return *this;
}
/*以下重载双等号 == */
//对象==对象
bool operator==(const test &t1)const{
return (v == t1.v);
}
//对象==int
bool operator==(const int &t1)const{
return (v == t1);
}
/*以下重载 输入>> 输出<< */
/*友元函数,输出对象*/
friend inline ostream & operator << (ostream & os, test &t1){
cout << "class t(" << t1.v << ")" << endl;
return os;
}
/*友元函数,输入对象*/
friend inline istream & operator >> (istream & is, test &t1){
cin >> t1.v;
return is;
}
};
int main(){
test t0, t1(3); // t0 has no initial value, so use default value 0
test t2(t1);
cout << t0 << t1 << t2;
cin >> t1;
t2 = t1;
t2 += t1;
t1 += 10;
cout << t2;
if(t1 < t2) cout << "t1 < t2";
else if(t1 == t2) cout << "t1 = t2";
else /* t1 > t2*/ cout << "t1 > t2";
cout <<endl;
system("echo Tom");
return 0;
}
/*
$ ./a.out
class t(0)
class t(3)
class t(3)
45
class t(90)
t1 < t2
Tom
*/
完整的代码在上面。但我不明白为什么括号中必须有“ostream & os”(见下文)?如果我删除“ostream & os”,就会出现很多错误。
friend inline ostream & operator << (ostream & os, test &t1){
cout << "class t(" << t1.v << ")" << endl;
return os;
}