0

对于按分数排名的普通用户来说,下面的查询很酷,但我需要一个具有相同排名结果的查询,以获取表中相同的分数

SET @rank = 0;
SELECT * FROM (
    SELECT @rank:=@rank + 1 AS rank,score, user_id FROM site_crossword_members ORDER BY score DESC 
) as tmp; 

谢谢

4

2 回答 2

2

您确定您给定的查询甚至可以正常工作吗?我记得ORDER BY要在 之后完成SELECT,从而使您的等级排序ID ASC或相似。

SELECT user_id, 
    CASE WHEN @score != score THEN @rank := @rank + 1 ELSE @rank END AS rank,
    @score := score AS dummy_value
FROM (  SELECT score, user_id
        FROM site_crossword_members, 
            (SELECT @rank := 0, @score := NULL) AS vars
        ORDER BY score DESC) AS h

缩短版:

SELECT user_id, 
    @rank := @rank + (@score != score) AS rank,
    @score := score AS dummy_value
FROM (  SELECT score, user_id
        FROM site_crossword_members, 
            (SELECT @rank := 0, @score := NULL) AS vars
        ORDER BY score DESC) AS h
于 2012-11-15T08:06:22.627 回答
2

试试这个查询(带变量的版本) -

SET @rank = 0;
SET @score = NULL;

SELECT
  rank, score, user_id
FROM (
  SELECT
    score,
    user_id,
    IF(@score = score, @rank := @rank + 1, @rank := 1) AS rank,
    @score := score
  FROM site_crossword_members
  ORDER BY score DESC
) t;
于 2012-11-15T08:06:42.980 回答