我有一个运行良好的查询,但有一个问题,它显示了我不想要的其他数据。
数据是每个用户名的最新数据。
这是查询:
SELECT
l.USER_KEY AS id,
l.USER_ID AS username,
gl1.CHAR_KEY AS char_id,
gl1.NAME AS charname,
gl1.GATENUM AS server,
CONVERT(VARCHAR(20), l.LOGINTIME, 100) AS user_time,
CONVERT(VARCHAR(20), gl1.OCCUR_TIME, 100) AS char_time
FROM LOG_CONNECT201211 AS gl1
JOIN game.dbo.CHAR_INFOR AS g --character data
ON gl1.CHAR_KEY = g.CHAR0_KEY OR gl1.CHAR_KEY = g.CHAR1_KEY OR gl1.CHAR_KEY = g.CHAR2_KEY
JOIN login.dbo.USER_CHECK_LOGIN AS l --login data
ON g.USER_KEY = l.USER_KEY
JOIN (SELECT char_key, max(OCCUR_TIME) as mostrecent --game logs
FROM LOG_CONNECT201211
WHERE KIND=20 OR KIND=21
GROUP BY char_key) AS gl2
ON gl2.char_key = gl1.char_key and gl2.mostrecent = gl1.OCCUR_TIME
WHERE l.CHECKLOGIN = 1
ORDER BY username DESC
返回:
id username char_id name map user_time char_time
------------------------------------------------------------------------------------
3667 zr5970 11002 warpath 4 Nov 15 2012 8:54AM Nov 7 2012 6:31AM
3667 zr5970 11004 bloodfines 4 Nov 15 2012 8:54AM Nov 7 2012 6:33AM
3667 zr5970 11003 hanzhou 1 Nov 15 2012 8:54AM Nov 15 2012 8:54AM
14999 yvacosta 52086 Creams 1 Nov 15 2012 8:17AM Nov 15 2012 8:17AM
23433 yurich 1911481 abal 5 Nov 15 2012 8:34AM Nov 9 2012 4:05PM
23433 yurich 1911482 yurich 5 Nov 15 2012 8:34AM Nov 15 2012 8:30AM
23433 yurich 1911483 sharmaine 5 Nov 15 2012 8:34AM Nov 15 2012 8:35AM
10967 yubiwamoi 33376 Dwina 1 Nov 15 2012 4:33AM Nov 15 2012 4:33AM
所以数据是正确的,但我只想为每个用户名返回一行。
在此数据上,用户名返回 3,有 3 个名称,但我想要的唯一名称是具有最新 char_time 的名称。
正确数据示例:
id username char_id name map user_time char_time
-----------------------------------------------------------------------------------
3667 zr5970 11003 hanzhou 1 Nov 15 2012 8:54AM Nov 15 2012 8:54AM
14999 yvacosta 52086 Creams 1 Nov 15 2012 8:17AM Nov 15 2012 8:17AM
23433 yurich 1911483 sharmaine 5 Nov 15 2012 8:34AM Nov 15 2012 8:35AM
10967 yubiwamoi 33376 Dwina 1 Nov 15 2012 4:33AM Nov 15 2012 4:33AM
请注意,我只显示了zr5970
最新的数据char_time
请指教,谢谢。