1

我有一个运行良好的查询，但有一个问题，它显示了我不想要的其他数据。

数据是每个用户名的最新数据。

这是查询：

SELECT
    l.USER_KEY AS id,
    l.USER_ID AS username, 
    gl1.CHAR_KEY AS char_id,
    gl1.NAME AS charname,
    gl1.GATENUM AS server,
    CONVERT(VARCHAR(20), l.LOGINTIME, 100) AS user_time,
    CONVERT(VARCHAR(20), gl1.OCCUR_TIME, 100) AS char_time
FROM LOG_CONNECT201211 AS gl1
    JOIN game.dbo.CHAR_INFOR AS g --character data
        ON gl1.CHAR_KEY = g.CHAR0_KEY OR gl1.CHAR_KEY = g.CHAR1_KEY OR gl1.CHAR_KEY = g.CHAR2_KEY
    JOIN login.dbo.USER_CHECK_LOGIN AS l --login data
        ON g.USER_KEY = l.USER_KEY
    JOIN (SELECT    char_key, max(OCCUR_TIME) as mostrecent  --game logs
            FROM    LOG_CONNECT201211 
            WHERE   KIND=20 OR KIND=21
            GROUP BY char_key) AS gl2
        ON gl2.char_key = gl1.char_key and gl2.mostrecent = gl1.OCCUR_TIME
WHERE l.CHECKLOGIN = 1
ORDER BY username DESC

返回：

id      username    char_id name        map user_time           char_time   
------------------------------------------------------------------------------------
3667    zr5970      11002   warpath     4   Nov 15 2012  8:54AM Nov  7 2012  6:31AM
3667    zr5970      11004   bloodfines  4   Nov 15 2012  8:54AM Nov  7 2012  6:33AM
3667    zr5970      11003   hanzhou     1   Nov 15 2012  8:54AM Nov 15 2012  8:54AM
14999   yvacosta    52086   Creams      1   Nov 15 2012  8:17AM Nov 15 2012  8:17AM
23433   yurich      1911481 abal        5   Nov 15 2012  8:34AM Nov  9 2012  4:05PM
23433   yurich      1911482 yurich      5   Nov 15 2012  8:34AM Nov 15 2012  8:30AM
23433   yurich      1911483 sharmaine   5   Nov 15 2012  8:34AM Nov 15 2012  8:35AM
10967   yubiwamoi   33376   Dwina       1   Nov 15 2012  4:33AM Nov 15 2012  4:33AM

所以数据是正确的，但我只想为每个用户名返回一行。

在此数据上，用户名返回 3，有 3 个名称，但我想要的唯一名称是具有最新 char_time 的名称。

正确数据示例：

id      username    char_id name        map user_time           char_time   
-----------------------------------------------------------------------------------
 3667   zr5970      11003   hanzhou     1   Nov 15 2012  8:54AM Nov 15 2012  8:54AM
14999   yvacosta    52086   Creams      1   Nov 15 2012  8:17AM Nov 15 2012  8:17AM
23433   yurich      1911483 sharmaine   5   Nov 15 2012  8:34AM Nov 15 2012  8:35AM
10967   yubiwamoi   33376   Dwina       1   Nov 15 2012  4:33AM Nov 15 2012  4:33AM

请注意，我只显示了zr5970最新的数据char_time

请指教，谢谢。

4

3 回答 3

0

首先选择用户名和最长时间。这样，您将拥有正确的行数。当您拥有它时，您可以轻松地将其他列添加到您的查询中......

于 2012-11-15T01:05:41.840 回答
0 
select a.USER_KEY AS id,
    l.USER_ID AS username, 
    gl1.CHAR_KEY AS char_id,
    gl1.NAME AS charname,
    gl1.GATENUM AS server,
    CONVERT(VARCHAR(20), l.LOGINTIME, 100) AS user_time,
   CONVERT(VARCHAR(20), gl1.OCCUR_TIME, 100) AS char_time
from 
(select user_key, max(occur_time) as mostrecent
from log_connect2011
WHERE   KIND=20 OR KIND=21
group by user_key) a
join LOG_CONNECT201211 AS gl1 on a.user_key = gl1.user_key and a.mostrecent =        gl1.occur_time 
JOIN game.dbo.CHAR_INFOR AS g --character data
  ON gl1.CHAR_KEY = g.CHAR0_KEY OR gl1.CHAR_KEY = g.CHAR1_KEY OR gl1.CHAR_KEY = g.CHAR2_KEY
JOIN login.dbo.USER_CHECK_LOGIN AS l --login data
  ON g.USER_KEY = l.USER_KEY
WHERE l.CHECKLOGIN = 1
ORDER BY username DESC
于 2012-11-15T01:51:12.370 回答
0

使用 ROW_NUMBER()

SELECT *
FROM
(
SELECT
    l.USER_KEY AS id,
    l.USER_ID AS username, 
    gl1.CHAR_KEY AS char_id,
    gl1.NAME AS charname,
    gl1.GATENUM AS server,
    CONVERT(VARCHAR(20), l.LOGINTIME, 100) AS user_time,
    CONVERT(VARCHAR(20), gl1.OCCUR_TIME, 100) AS char_time,
    rn = row_number() over (partition by l.USER_KEY order by gl1.OCCUR_TIME DESC)
FROM LOG_CONNECT201211 AS gl1
    JOIN game.dbo.CHAR_INFOR AS g --character data
        ON gl1.CHAR_KEY = g.CHAR0_KEY OR gl1.CHAR_KEY = g.CHAR1_KEY OR gl1.CHAR_KEY = g.CHAR2_KEY
    JOIN login.dbo.USER_CHECK_LOGIN AS l --login data
        ON g.USER_KEY = l.USER_KEY
WHERE l.CHECKLOGIN = 1
) X
WHERE rn=1
ORDER BY username DESC
于 2012-11-15T02:20:34.487 回答