我尝试用 JSON 这个我的程序完成我的程序
package udin.tes2;
import java.util.ArrayList;
import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
public class LihatInfo extends Activity {
TextView error,br1;
String i,id_kepadatan,returnString;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.lihat_info);
br1=(TextView)findViewById(R.id.tv_error);
}
public void clickHandler(View view){
Intent a = null;
id_kepadatan = "5";
switch (view.getId()){
case R.id.lihatInfo:
ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
postParameters.add(new BasicNameValuePair("id_kepadatan", id_kepadatan));
/* String valid = "1";*/
String response = null;
try {
response = CustomHttpClient.executeHttpPost("http://10.0.2.2/android/cek.php", postParameters);
String result = response.toString();
//parse json data
try{
returnString = "";
JSONArray jArray = new JSONArray(result);
for(int i=0;i<jArray.length();i++){
JSONObject json_data = jArray.getJSONObject(i);
Log.i("log_tag","id_kepadatan: "+json_data.getInt("id_kepadatan")+
", username: "+json_data.getString("username")+
", nama_jalan: "+json_data.getString("nama_jalan")+
", status: "+json_data.getString("status")+
", tanggal: "+json_data.getString("tanggal")+
", waktu: "+json_data.getString("waktu")+
", keterangan: "+json_data.getString("keterangan")
);
//Get an output to the screen
returnString += "\n" + json_data.getString("nama_jalan") + " -> "+ json_data.getString("status")+ " pada "+ json_data.getString("tanggal")+ " waktu "+ json_data.getString("waktu")+ " karena "+ json_data.getString("keterangan");
}
}
catch(JSONException e){
Log.e("log_tag", "Error parsing data "+e.toString());
}
try{
br1.setText(returnString);
}
catch(Exception e){
Log.e("log_tag","Error in Display!" + e.toString());;
}
}
catch (Exception e) {
Log.e("log_tag","Error in http connection!!" + e.toString());
}
break;
case R.id.kembali2:
a = new Intent(this, Menu.class);
startActivity(a);
break;
}
}
}
这是我的 lihatInfo.php 文件
<?php
$conn = mysql_connect("localhost","root","");
mysql_select_db("proyek akhir");
$query = "SELECT * FROM kepadatan WHERE id_kepadatan > '". $_POST["id_kepadatan"]."'";
$result = mysql_query($query);
while($row=mysql_fetch_assoc($result))
$output[]=$row;
print(json_encode($output));
mysql_close();
?>
但是当我部署到模拟器时,它说
“显示错误!Java.lang.NullPointerException”
你能帮助我吗?我只有 2 天完成这个请帮帮我....谢谢