tsql - SELECT Columns WHERE 一列是不同的？

Question

谁能帮我查询？

我尝试了以下方法，但出现错误

SELECT Column1, Column2, Column3 FROM Table WHERE [Column1] NOT IN 
(SELECT [Column1] FROM Table GROUP BY [Column1] HAVING COUNT([Column]) > 1)

子查询 [Column1] 中的 MEMO、OLE 或超链接对象无效。

Answer 1

使用Group BywithHaving子句：

SELECT Column1, MIN(Column2)AS Column2, MIN(Column3)AS Column3
FROM dbo.Table
GROUP BY Column1
HAVING ( COUNT(Column1) = 1 )

应该可以工作，因为每个“组”只有一行。

Answer 2

您的原始查询应该可以工作，您只有 column 而不是 column1。

 SELECT Column1, Column2, Column3 FROM TableName WHERE [Column1] NOT IN 
(SELECT [Column1] FROM TableName GROUP BY [Column1] HAVING COUNT(Column1) > 1)

见：http ://sqlfiddle.com/#!3/d99a8/5/0

Answer 3

据我所知，您需要 [Column1] 唯一的所有数据（仅出现一次）

DECLARE @x TABLE (col1 INT, col2 INT, col3 INT)

INSERT INTO @x
        ( [col1], [col2], [col3] )
VALUES  ( 1, 2, 3  )
        ,( 1, 4, 5 )
        ,( 2, 6, 7 )

SELECT * FROM @x

SELECT col1, col2 , col3 FROM @x
WHERE col1 NOT IN 
    ( SELECT [col1]  FROM @x GROUP BY [col1] HAVING  COUNT(*) > 1 )