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我正在使用 SPServices(GetListItems 方法)从共享点列表中获取一些信息。该列表包含一个“人员或组”类型字段,该字段返回用户的数字 ID 和名称(显示名称),以分号分隔,例如“43#;John Doe”。我需要该字段中所有用户的电子邮件地址(在所有返回的行中)。任何人都可以帮忙吗?提前致谢。

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2 回答 2

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保罗你摇滚:)

从保罗的最后评论中,我得到了所需的东西。这是完美的。:)

您唯一需要的是将以下内容添加到调用中

CAMLQueryOptions: "<QueryOptions><ExpandUserField>True</ExpandUserField></QueryOptions>",

所以我的示例调用变成了这个

$().SPServices({ operation: "GetListItems", async: false, listName: "Assignees", webURL: "https://col.wow.telenor.com/sites/go/",
            CAMLViewFields: "<ViewFields Properties='True'/>",
            CAMLQuery: "",
            CAMLQueryOptions: "<QueryOptions><ExpandUserField>True</ExpandUserField></QueryOptions>",
            completefunc: function (xData,Status) {

                $(xData.responseXML).SPFilterNode("z:row").each(function () {

                    try {
                    //ows_Name1 is a field of type "People or Group" the after adding CAMLQueryOptions this field returns all the fields
                    // propeties of user i.e. Displayname,ID,email id, domain login, sip ID etc all separate by #
                        var title = $(this).attr("ows_Name1"); 
                    // Splitting the resultant string with # give you string array of all the properties. In my case email ID is at 
                    // index 3.
                        var userEmail = userText.split('#')[3];
                    // Below line is added to remove the trailing "," from email id
                        userEmail = userEmail.substring(0,userEmail.indexOf(','));

                    }
                    catch (e) {
                        alert('Exception: ' + e.message);
                    }
                });
            }
        });

对不起,保罗,我必须取消标记你的答案并做出这个答案:)

于 2012-11-20T16:07:59.577 回答
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@Mujaba,

我之前通过获取用户名并使用 People 服务和 SearchPrincipals 方法进行搜索来完成此操作...这是一个示例:

var userEmail = '';
var userId    = '43';
$().SPServices({
    operation:      "SearchPrincipals",
    searchText:     "John Doe",
    async:          true,
    completefunc:   function(xData, status){
        $(xData.responseXML).find("PrincipalInfo")
            .each(function(){
                var thisUser = $(this);
                if ($.trim(thisUser.find("UserInfoID").text()) == userId) {
                    userEmail = $.trim(thisUser.find("Email").text());

                    alert("User's email: " + userEmail);

                    return false;
                }
            });
    }
});

保罗。

于 2012-11-14T18:19:02.100 回答