我有一些在 MSVC 上编译得很好的代码,但现在我将它移植到 Clang 并且在编写赋值运算符时遇到了麻烦,我猜这在 MSVC 中被认为是隐含的。这是我得到的代码:
enum EBufferPacking {
Invalid = -1, UInt1, Int8, Int16, Float32
};
template<EBufferPacking p>
class PackedBufferRef;
template<>
class PackedBufferRef<UInt1> {
unsigned char *const m_pBuffer;
const unsigned char m_nMask;
public:
explicit PackedBufferRef<UInt1>(void *buffer, int offset):
m_pBuffer((unsigned char *)buffer + offset/8),
m_nMask(1<<(offset%8))
{}
operator float() const
{
return (*m_pBuffer & m_nMask) ? 1.0f : 0.0f;
}
template<class T>
PackedBufferRef<UInt1> &operator =(const T &t)
{
if (!t) // write 0
*m_pBuffer &= ~m_nMask;
else
*m_pBuffer |= m_nMask;
return *this;
}
PackedBufferRef<UInt1> &operator =(const PackedBufferRef<UInt1> &ref)
{
if( !(*ref.m_pBuffer & ref.m_nMask) )
*m_pBuffer &= ~m_nMask;
else
*m_pBuffer |= m_nMask;
return *this;
}
};
template<class T>
class BytePackedBufferRef{
protected:
T *const m_pBuffer; // dont assign new pointers
BytePackedBufferRef<T>(void *buffer, int offset): m_pBuffer((T *)buffer + offset) {}
BytePackedBufferRef &operator=(const BytePackedBufferRef &other) {
// assignment operator should go here
}
public:
operator T*() const { return m_pBuffer; }
operator T() const { return *m_pBuffer; }
};
template<>
class PackedBufferRef<Float32>:public BytePackedBufferRef<float> {
public:
explicit PackedBufferRef<Float32>(void *buffer, int offset):BytePackedBufferRef<float>(buffer, offset) {}
template<class T> PackedBufferRef<Float32> &operator =(const T &t) { *m_pBuffer = (float)t; return *this; }
};
int main()
{
float fx = 0.5f;
float fy = 1.7f;
PackedBufferRef<Float32> firstRef(&fx, 0);
PackedBufferRef<Float32> secondRef(&fy, 0);
firstRef = secondRef;
printf("First ref: %.2f\n", (float)firstRef);
printf("Second ref: %.2f\n", (float)secondRef);
return 0;
}
从 main 函数你可以看到我想要的结果:我想m_pBuffer
从赋值的 RHS 上的变量中取出,并将其放入m_pBuffer
LHS 变量上。PackedBufferRef 特化有一个赋值运算符来执行此操作,但它只是将赋值传递给BytePackedBufferRef
类型,其m_pBuffer
成员声明为 const。在这种情况下,我该如何编写赋值运算符?