php - 按 where 条件排序

Question

我有以下查询：

select `state` from `table1` 
where `state` in ('NC','North Carolina','TN','Tennessee','CO','Colorado','NM','New Mexico','UT','Utah')
limit 200 offset 0

我需要按state出现在我的where子句中的结果排序（即 first NC， then TN， then CO，依此类推）。

我怎样才能做到这一点？我尝试使用order by，但没有给出这个结果。

Answer 1

您可以使用ORDER BY FIELD

SELECT `state`
FROM `table1`
WHERE `state` IN ('NC','North Carolina','TN','Tennessee','CO','Colorado','NM','New Mexico','UT','Utah')
ORDER BY FIELD(`state`, 'NC','North Carolina','TN','Tennessee','CO','Colorado','NM','New Mexico','UT','Utah');

• SQLFiddle 演示

Answer 2

SELECT col_name
FROM table_nane
WHERE col_nane IN ('NC','North Carolina','TN','Tennessee','CO','Colorado','NM','New Mexico','UT','Utah')
ORDER BY FIELD(`state`, 'NC',.....);

等等....

Answer 3

尝试这个：

order by case when `state`='NC' or `state`='North Carolina' then 1 
              when `state`='TN' or `state`='Tennessee' then 2
              when `state`='CO' or `state`='Colorado' then 3
         end 

Answer 4

您可以结合ORDER BY一个CASE WHEN构造：

ORDER BY CASE 
            WHEN state = 'NC' THEN 1
            WHEN state = 'North Carolina' THEN 2
            ...
         END