css - 如何显示关闭图标活动状态

Question

我有一个带有搜索图标的输入字段。当输入字段被按下/聚焦时，我希望在输入框上显示一个关闭图标，如下图所示

jsfiddle

<div id="search-controls">
   <input type="text" class="search-box in-acvtive" placeholder="e.g. restaurant name, cuisine" />
</div>

#search-controls {
    height: 68px;
    padding: 5px;
}

#search-controls input.ui-input-text {
    height: 26px;
    background: url('../img/search-icon.png') 99.5% center no-repeat;
    background-size: 16px 14px;
    border: 1px solid #999;
    -moz-border-radius: 2px;
    border-radius: 2px;
    -moz-box-shadow: inset 0px 5px 10px -5px #BBB;
    -webkit-box-shadow: inset 0px 5px 10px -5px #BBB;
    box-shadow: inset 0px 0px 5px 10px -5px #BBB;
    padding: 6px 5px 0 5px;
    margin: 0 0 5px 0;
    font-size: 15px;
    line-height: 15px;
}

#search-controls input.ui-input-text.ui-focus {
    border: 1px solid #9E0249;
    border-radius: 2px;
    -moz-border-radius: 2px;
    -webkit-border-radius: 2px;
    box-shadow: none;
    moz-box-shadow: none;
    -webkit-box-shadow: none;
    background: url('../img/search-active-icon.png') 100% center no-repeat;
}

Answer 1

尝试这样的事情 -演示

HTML

<div id="header" class="search" data-role="header" data-position="fixed">
    <div id="search-controls">
        <input type="text" class="search-box" placeholder="e.g. restaurant name, cuisine" />
        <span> x </span>        
    </div><!-- /search-controls -->
</div>​

CSS

#search-controls span {
    display: none;
    position: absolute;
    top: 11px;
    right: 35px;
    height: 22px;
    width: 22px;
    background: #bbb;
    border-radius: 20px;
    color: #fff;
    font: 400 20px/22px 'Lucida Console', sans-serif;
    text-align: center;
    border: 1px solid #bbb;
    cursor: pointer;
}

#search-controls input.ui-input-text.ui-focus ~ span {
    display: block;
}