我想计算问题中的“总分”与问题中每个答案的文本输入之间的差异。此外,如果一个问题只有一个答案,那么它应该将文本输入显示为只读,并显示与该文本输入中该问题的“总分”下的数字相同的值。
下面是一个屏幕截图,显示了表格和我在这两种情况下遇到的书面问题:
下面是当前的 jquery 变量,它应该进行计算并在必要时显示只读文本框。但目前它不起作用。另外,目前我在计算时将总分的数字显示为“5”,这是不正确的,因为它应该是每行内的数字,所以我相信$sessionMarks
应该是数字的变量,而不是 5。
$(function(){
var questions = $('#markstbl td[class*="_ans"]').length-1;
//disable single entry
for (var i=0;i<=questions;i++){
if($("[class*=q"+i+"_mark]").length ==1){
$("[class*=q"+i+"_mark]").attr("disabled","disabled")
}
}
//find each question set and add listeners
for (var i=0;i<=questions;i++){
$('input[class*="q'+i+'"]').keyup(function(){
var cl = $(this).attr('class').split(" ")[1]
var questionno = cl.substring(cl.indexOf('q')+1,cl.indexOf('_'))
var t=0;
$("[class*=q"+questionno+"_mark]").each(function(){
var num = (isNaN(parseInt($(this).val())))?0:parseInt($(this).val());
t+=parseInt(num);
})
var fixedno = 5;
$(".q"+questionno+"_ans").text((t>fixedno)?fixedno:t);
})
}
})
下面是表格的代码,它从查询中输出数据库中每个问题的详细信息,然后将其显示在表格中:
<?php
$assessment = $_SESSION['id'] . $sessionConcat;
include('connect.php');
$query = "SELECT q.SessionId, s.SessionName, q.QuestionId, q.QuestionContent, an.Answer, q.QuestionMarks
FROM Session s
INNER JOIN Question q ON s.SessionId = q.SessionId
JOIN Answer an ON q.QuestionId = an.QuestionId AND an.SessionId = q.SessionId
WHERE s.SessionName = ?
ORDER BY q.QuestionId, an.Answer
";
// prepare query
$stmt=$mysqli->prepare($query);
// You only need to call bind_param once
$stmt->bind_param("s", $assessment);
// execute query
$stmt->execute();
// This will hold the search results
$searchQuestionId = array();
$searchQuestionContent = array();
$searchAnswer = array();
$searchMarks = array();
// Fetch the results into an array
// get result and assign variables (prefix with db)
$stmt->bind_result($dbSessionId, $dbSessionName, $dbQuestionId, $dbQuestionContent, $dbAnswer, $dbQuestionMarks);
while ($stmt->fetch()) {
$searchQuestionId[] = $dbQuestionId;
$searchQuestionContent[] = $dbQuestionContent;
$searchAnswer[] = $dbAnswer;
$searchMarks[] = $dbQuestionMarks;
}
?>
....
<tbody>
<tr>
<?php
$previous_question_id = null;
$rowspans = array_count_values($searchQuestionId);
$output = "";
$questionid = 0; //whole question
$questionno = 0; //part of question
foreach ($searchQuestionContent as $key => $question) {
if ($previous_question_id != $searchQuestionId[$key]){
$questionno=0;
}
// removed logic, not necessary to set empty strings if you're skipping them
$output.= '<tr class="questiontd">' . PHP_EOL;
if ($previous_question_id != $searchQuestionId[$key]) {
$output.= '<td class="questionnumtd" name="numQuestion" rowspan="' . $rowspans[$searchQuestionId[$key]] . '">' . htmlspecialchars($searchQuestionId[$key]) . '</td>' . PHP_EOL;
$output.= '<td class="questioncontenttd q{$questionno++}_mark{$questionid}" rowspan="' . $rowspans[$searchQuestionId[$key]] . '">' . htmlspecialchars($question) . '</td>' . PHP_EOL;
}
$output.= '<td class="answertd" name="answers[]">';
$output.= $searchAnswer[$key];
$output.= '</td>';
$output.= '<td class="answermarkstd"><input class="individualMarks" q_group="1" name="answerMarks[]" id="individualtext" type="text" /></td>' . PHP_EOL;
if ($previous_question_id != $searchQuestionId[$key]) {
$output.= '<td class="noofmarkstd q{$questionid++}_ans" q_group="1" rowspan="' . $rowspans[$searchQuestionId[$key]] . '">' . htmlspecialchars($searchMarks[$key]) . '</td>' . PHP_EOL;
}
// moved this to the end
if ($previous_question_id != $searchQuestionId[$key]) {
$previous_question_id = $searchQuestionId[$key];
}
}
echo $output;
?>
</tr>
</tbody>
更新:
在这个小提琴中的示例 HTML 中,我可以让它工作(除了我希望计算是总分减去文本输入中输入的数字,而不是它现在正在做的事情,即当我在文本输入中输入一个数字时执行从 0 到文本输入中输入的任何数字的加法),但是当我尝试编辑上面的代码来做同样的事情时,它不起作用,什么也没有发生。
示例 html 如下:
<form id="Marks" action="/u0867587/Mobile_app/individualmarks.php" method="post">
<table border='1' id='markstbl'>
<thead>
<tr>
<th class='questionth'>Question No.</th>
<th class='questionth'>Question</th>
<th class='answerth'>Answer</th>
<th class='answermarksth'>Marks per Answer</th>
<th class='noofmarksth'>Total Marks</th>
</tr>
</thead>
<tbody>
<tr class="questiontd">
<td class="questionnumtd" name="numQuestion" rowspan="3">1</td>
<td class="questioncontenttd" rowspan="3">Name three features in a ROM</td>
<td class="answertd" name="answers[]">A</td>
<td class="answermarkstd">
<input class="individualMarks q0_mark_0" q_group="1" name="answerMarks[]" id="individualtext" type="text" />
</td>
<td class="noofmarkstd q0_ans" q_group="1" rowspan="3">5</td>
</tr>
<tr class="questiontd">
<td class="answertd" name="answers[]">B</td>
<td class="answermarkstd">
<input class="individualMarks q0_mark_1" q_group="1" name="answerMarks[]" id="individualtext" type="text" />
</td>
</tr>
<tr class="questiontd">
<td class="answertd" name="answers[]">D</td>
<td class="answermarkstd">
<input class="individualMarks q0_mark_2" q_group="1" name="answerMarks[]" id="individualtext" type="text" />
</td>
</tr>
<tr class="questiontd">
<td class="questionnumtd" name="numQuestion" rowspan="1">2</td>
<td class="questioncontenttd" rowspan="1">Here is a single answer</td>
<td class="answertd" name="answers[]">True</td>
<td class="answermarkstd">
<input class="individualMarks q1_mark_0" q_group="1" name="answerMarks[]" id="individualtext" type="text" />
</td>
<td class="noofmarkstd q1_ans" q_group="1" rowspan="1">5</td>
</tr>
</tbody>
</table>
</form>
下面是数据库表的样子,(这将遵循与屏幕截图中相同的数据)
会话表:(存储考试详细信息的位置)
SessionId SessionName
1 AAA
问题表:(存储每个考试的问题)
SessionId QuestionId QuestionContent Total Marks
1 1 Name three features in a ROM 5
1 2 Here is a single answer 5
答案表:(存储每个考试中每个问题的答案)
AnswerId(auto) SessionId QuestionId Answer
1 1 1 A
2 1 1 B
3 1 1 D
4 1 2 True
Individual_Answer 表:(存储每个单独答案的每个单独标记)
AnswerId AnswerMarks
1 2
2 2
3 1
4 5