0

我的数据库中有一个城市列表。有一个编辑按钮，可以打开一个带有表单的模式，他们可以在其中更改城市名称并提交。我很难让 city_id 从编辑按钮通过模态传递到控制器。我在尝试将 city_id 放入表单开放代码的行中收到“city_id 的未定义变量”消息。

在混合中添加模态让我感到困惑。

查看代码

<a href="#" class="btn edit-modal" data-id="<?php echo $c['city_id']; ?>"  data-name="<?php echo  $c['city_name']; ?>">Edit</a>

<!-- Modal for Edit -->
<div class="modal hide" id="editCityDialog">
<div class="modal-header">
    <button class="close" data-dismiss="modal">x</button>
    <h3>Edit City</h3>
</div>
<div class="modal-body">
    <?php $this->load->helper('form'); ?>
        <?php echo form_open('/cities/edit_city/'. $city_id); ?>
        <label class="control-label" for="name">City</label>
        <input type="text" name="city_name" id="city_name" value=""/><br />
        <input type="submit" class="btn-small btn-primary" value="Edit City" />
        <button class="btn-small" data-dismiss="modal">Cancel</button>
    <?php echo form_close(); ?>
</div>


<!-- jQuery for Modal -->
<script>
  // scripts for modal windows
$(document).on("click", ".edit-modal", function () {
    var city_name = $(this).data('name');
    var city_id = $(this).data('id');
    $(".modal-body #city_name").val( city_name );
    $('#editCityDialog').modal('show');
});
</script>

控制器代码

// Edit City
public function edit_city() {
    $id = $this->uri->segment(3);

    if ($this->input->city('submit')) {
        $city_name = $this->input->xss_clean($this->input->city('city_name'));
        $this->cities_model->edit_city($city_id, $city_name);
    }
}

型号代码

// Edit City
public function edit_city($city_id, $city_name) {
    $data = array(
        'city_name' => $city_name
    );
    $this->db->where('city_id', $city_id);
    $this->db->update('cities', $data);
}
4

2 回答 2

1

您可以使用city_id已有的并设置操作：

$(document).on("click", ".edit-modal", function () {
    var city_name = $(this).data('name');
    var city_id = $(this).data('id');
    $(".modal-body #city_name").val( city_name );
    //set the forms action to include the city_id
    $(".modal-body form").attr('action','/cities/edit_city/'+city_id);
    $('#editCityDialog').modal('show');
});
于 2012-11-13T18:04:56.367 回答
0

如果回<?php echo $c['city_id']; ?>显适用于编辑按钮，您应该像这样对 form_open 执行此操作

<?php echo form_open('/cities/edit_city/'. $c['city_id']); ?>

我还建议，如果您的edit_city()函数仅在有 a 时才被调用segment(3)，那么这样做会更容易：

// Edit City
public function edit_city($id) {

    if ($this->input->city('submit')) {
        $city_name = $this->input->xss_clean($this->input->city('city_name'));
        $this->cities_model->edit_city($city_id, $city_name);
    }
}
于 2012-11-13T17:26:34.027 回答