我正在为我的 asp.net mvc4 应用程序开发社交网络集成。
Twitter 和 Facebook 对我来说很容易，但我严重坚持使用 LinkedIn。
这是我的代码。
public ActionResult LinkedInTest(string text)
{
var client = new RestClient
{
Authority = "https://api.linkedin.com/uas/oauth",
Credentials = LinkedInSocialHelper.GetCredentials()
};
var request = new RestRequest {Path = "requestToken"};
RestResponse response = client.Request(request);
token = response.Content.Split('&')[0].Split('=')[1];
tokenSecret = response.Content.Split('&')[1].Split('=')[1];
textToPost = text;
Response.Redirect("https://api.linkedin.com/uas/oauth/authorize?oauth_token=" + token + "&scope=r_basicprofile+r_emailaddress+r_network+r_contactinfo+rw_nus");
return null;
textToPost = text;
return RedirectToAction("LinkedInCallback");
}
public ActionResult LinkedInCallback()
{
verifier = Request["oauth_verifier"];
var client = new RestClient
{
Authority = "https://api.linkedin.com/uas/oauth",
Credentials = LinkedInSocialHelper.GetCredentials(token, tokenSecret, verifier),
Method = WebMethod.Post
};
var request = new RestRequest {Path = "accessToken"};
RestResponse response = client.Request(request);
token = response.Content.Split('&')[0].Split('=')[1];
tokenSecret = response.Content.Split('&')[1].Split('=')[1];
LinkedInSocialHelper.Post(textToPost, token, tokenSecret);
return RedirectToAction("Calendar");
}
public static void Post(string text, string accessToken, string accessTokenSecret)
{
var tokenManager = new TokenManager(ApiKey, ApiSecret);
tokenManager.ExpireRequestTokenAndStoreNewAccessToken(null, null, accessToken, accessTokenSecret);
var authorization = new WebOAuthAuthorization(tokenManager, UserToken);
LinkedInService service = new LinkedInService(authorization);
//var user = service.GetCurrentUser(ProfileType.Public); - IT IS GIVING ME THE SAME ERROR - Access denied
service.CreateShare(text, VisibilityCode.ConnectionsOnly);
}
一切正常，除了最后一件事 - 发布共享 - 尽管我使用所有必要的权限生成令牌，但我可以访问发布共享被拒绝异常：
"https://api.linkedin.com/uas/oauth/authorize?oauth_token=" + token + "&scope=r_basicprofile+r_emailaddress+r_network+r_contactinfo+rw_nus"
希望各位好心人帮帮我。