params = {'file': open("test.txt", "rb"), 'name': 'upload test'}
datagen, headers = poster.encode.multipart_encode(params)
request = urllib2.Request(upload_url, datagen, headers)
result = urllib2.urlopen(request)
我使用海报库来发布 HTTP。它运作良好。我对此很满意。
但我想尝试一些东西。如您在上面看到的,要发送文件数据,我必须打开一个文件。但是有没有办法不制作一个真正的文件来做到这一点?我们可以使用 STREAM, likeStringIO
来处理文件之类的数据,对吗?但是,我不是很了解poster
。所以,我想知道使用 STREAM 的方法poster
。
添加
实际上,我试图发布图像数据。我在下面写了这个
from PyQt4 import QtCore, QtGui
from poster.encode import multipart_encode
from poster.streaminghttp import register_openers
import urllib2, os
register_openers()
app = QtGui.QApplication(sys.argv)
pixmap = QtGui.QPixmap("c:/test_img.png")
byte_array = QtCore.QByteArray()
buffer = QtCore.QBuffer(byte_array)
buffer.open(QtCore.QIODevice.WriteOnly)
pixmap.save(buffer, "PNG")
from cStringIO import StringIO
datagen, headers = multipart_encode({"image": StringIO(str(byte_array.toBase64()))})
request = urllib2.Request(upload_url, datagen, headers)
_rnt = urllib2.urlopen(request)
但是,我收到此错误:
Traceback (most recent call last):
File "<pyshell#25>", line 1, in <module>
_rnt = urllib2.urlopen(request)
File "C:\Python26\lib\urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "C:\Python26\lib\urllib2.py", line 397, in open
response = meth(req, response)
File "C:\Python26\lib\urllib2.py", line 510, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python26\lib\urllib2.py", line 435, in error
return self._call_chain(*args)
File "C:\Python26\lib\urllib2.py", line 369, in _call_chain
result = func(*args)
File "C:\Python26\lib\urllib2.py", line 518, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 500: Internal Server Error