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我正在开发一个脚本，它需要一篇文章，在文章中搜索“关键字”，然后用锚链接随机替换该关键字。

我让脚本正常工作，但是我需要能够为函数循环并插入随机位置的“替换”数组。

所以第一个随机位置将获得锚链接#1。第二个随机位置将获得锚链接#2。第三个随机位置将获得锚链接#3。ETC...

我在这里找到了我的问题的一半答案： PHP replace a random word of a string

public function replace_random ($str, $search, $replace, $n) {

    // Get all occurences of $search and their offsets within the string
    $count = preg_match_all('/\b'.preg_quote($search, '/').'\b/', $str, $matches, PREG_OFFSET_CAPTURE);

    // Get string length information so we can account for replacement strings that are of a different length to the search string
    $searchLen = strlen($search);
    $diff = strlen($replace) - $searchLen;
    $offset = 0;

    // Loop $n random matches and replace them, if $n < 1 || $n > $count, replace all matches
    $toReplace = ($n < 1 || $n > $count) ? array_keys($matches[0]) : (array) array_rand($matches[0], $n);
    foreach ($toReplace as $match) {
        $str = substr($str, 0, $matches[0][$match][1] + $offset).$replace.substr($str, $matches[0][$match][1] + $searchLen + $offset);
        $offset += $diff;
    }

    return $str;

}

所以我的问题是，如何更改此函数以接受 $replace 变量的数组？

编辑 我还尝试从 mt_rand 获取随机数组键，它从替换数组中输出我的替换，但它仍然只在整个内容中添加一个替换。我希望该函数为它找到的 $search 变量的每个实例选择一个“关键字”。

public function replace_random ($str, $search, $replace, $n) {

    // Get all occurences of $search and their offsets within the string
    $count = preg_match_all('/\b'.preg_quote($search, '/').'\b/', $str, $matches, PREG_OFFSET_CAPTURE);

    // Get string length information so we can account for replacement strings that are of a different length to the search string
    $searchLen = strlen($search);
    $diff = strlen($replace) - $searchLen;
    $offset = 0;

    $searchCount = count($replace);
    $arrayNum = mt_rand(0, 4);

    // Loop $n random matches and replace them, if $n < 1 || $n > $count, replace all matches
    $toReplace = ($n < 1 || $n > $count) ? array_keys($matches[0]) : (array) array_rand($matches[0], $n);
    foreach ($toReplace as $match) {
        $str = substr($str, 0, $matches[0][$match][1] + $offset).$replace[$arrayNum].substr($str, $matches[0][$match][1] + $searchLen + $offset);
        $offset += $diff;
    }

    return $str;

}
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1 回答 1

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解决方案原来我需要在 foreach 循环中添加一个变量：

$replaceRand    =   $replace[array_rand($replace)];

并在 $str 变量中调用它：

$str = substr($str, 0, $matches[0][$match][1] + $offset).$replaceRand.substr($str, $matches[0][$match][1] + $searchLen + $offset);

整个代码最终是：

public function replace_random ($str, $search, $replace, $n) {

    // Get all occurences of $search and their offsets within the string
    $count = preg_match_all('/\b'.preg_quote($search, '/').'\b/', $str, $matches, PREG_OFFSET_CAPTURE);

    // Get string length information so we can account for replacement strings that are of a different length to the search string
    $searchLen = strlen($search);
    $diff = strlen($replace) - $searchLen;
    $offset = 0;

    // Loop $n random matches and replace them, if $n < 1 || $n > $count, replace all matches
    $toReplace = ($n < 1 || $n > $count) ? array_keys($matches[0]) : (array) array_rand($matches[0], $n);
    foreach ($toReplace as $match) {
        $replaceRand    =   $replace[array_rand($replace)];
        $str = substr($str, 0, $matches[0][$match][1] + $offset).$replaceRand.substr($str, $matches[0][$match][1] + $searchLen + $offset);
        $offset += $diff;
    }

    return $str;

}
于 2012-11-13T14:50:18.630 回答