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在将现有的有状态服务公开为 RESTfull 服务的过程中。

我不想对任何现有的 java 类进行任何更改。我已经能够配置其他注释，例如 @path、@GET 使用spring-config.xml

弹簧配置.xml

<!-- Inquiry Services -->
    <bean id="retrieveContactHistoryBP" class="com.csc.fs.ws.contact.history.impl.RetrieveContactHistoryBPService"/>        
    <!-- Update Services -->
    <bean id="startContactBP" class="com.csc.fs.ws.contact.impl.StartContactBPService"/>

    <!-- REST services -->
    <bean id="startContactBPRest" class="com.csc.fs.rest.contact.StartContactBP" scope="prototype" />
    <bean id="retrieveContactHistoryBPRest" class="com.csc.fs.rest.contact.RetrieveContactHistoryBP" scope="prototype" />

    <!-- Exposing beans as rest services -->
    <jaxrs:server id="restServer" address="/rest/">
        <jaxrs:model id="restModel">
            <jaxrs:resource name="com.csc.fs.rest.contact.RetrieveContactHistoryBP" path="retrieveContactHistoryBP">
                <jaxrs:operation name="retrieve" path="{partyId}" consumes="application/json" produces="application/json" verb="GET">
                    <jaxrs:param name="req" type="CONTEXT"/>
                    <jaxrs:param name="partyId" type="PATH"/>
                </jaxrs:operation>
            </jaxrs:resource>
            <jaxrs:resource name="com.csc.fs.rest.contact.StartContactBP" path="startContactBP">
                <jaxrs:operation name="startContact" path="/" consumes="application/json" produces="application/json" verb="PUT">
                    <jaxrs:param name="req" type="CONTEXT"/>
                    <jaxrs:param name="startContact" type="REQUEST_BODY"/>
                </jaxrs:operation>
            </jaxrs:resource>
        </jaxrs:model>
        <jaxrs:serviceBeans>
<!--             <ref bean="startContactBPRest"/> --> <!-- Instead configure above -->
<!--             <ref bean="retrieveContactHistoryBPRest"/> -->
        </jaxrs:serviceBeans>
        <jaxrs:extensionMappings>
            <entry key="feed" value="application/atom+xml"/>
            <entry key="json" value="application/json"/>
            <entry key="xml" value="application/xml"/>
            <entry key="html" value="text/html"/>
        </jaxrs:extensionMappings>

        <jaxrs:providers>
            <ref bean="jaxbProvider"/>
            <ref bean="jsonProvider" />
        </jaxrs:providers>
    </jaxrs:server>

我面临的问题是@XmlRootElement. 我没有成功通过xml配置它。

尝试访问 REST 服务时出现以下错误

org.apache.cxf.interceptor.Fault
    org.apache.cxf.interceptor.AbstractFaultChainInitiatorObserver.onMessage(AbstractFaultChainInitiatorObserver.java:67)
    org.apache.cxf.phase.PhaseInterceptorChain.doIntercept(PhaseInterceptorChain.java:315)
    org.apache.cxf.transport.ChainInitiationObserver.onMessage(ChainInitiationObserver.java:113)
    org.apache.cxf.transport.servlet.ServletDestination.invoke(ServletDestination.java:105)
    org.apache.cxf.transport.servlet.ServletController.invokeDestination(ServletController.java:461)
    org.apache.cxf.transport.servlet.ServletController.invoke(ServletController.java:188)
    org.apache.cxf.transport.servlet.AbstractCXFServlet.invoke(AbstractCXFServlet.java:148)
    org.apache.cxf.transport.servlet.AbstractHTTPServlet.handleRequest(AbstractHTTPServlet.java:179)
    org.apache.cxf.transport.servlet.AbstractHTTPServlet.doGet(AbstractHTTPServlet.java:108)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
    org.apache.cxf.transport.servlet.AbstractHTTPServlet.service(AbstractHTTPServlet.java:159)


root cause 

java.lang.NullPointerException
    org.apache.cxf.jaxrs.model.wadl.WadlGenerator.handleOperation(WadlGenerator.java:310)
    org.apache.cxf.jaxrs.model.wadl.WadlGenerator.handleResource(WadlGenerator.java:253)
    org.apache.cxf.jaxrs.model.wadl.WadlGenerator.handleRequest(WadlGenerator.java:185)
    org.apache.cxf.jaxrs.impl.RequestPreprocessor.checkMetadataRequest(RequestPreprocessor.java:189)
    org.apache.cxf.jaxrs.impl.RequestPreprocessor.preprocess(RequestPreprocessor.java:82)
    org.apache.cxf.jaxrs.interceptor.JAXRSInInterceptor.processRequest(JAXRSInInterceptor.java:112)
    org.apache.cxf.jaxrs.interceptor.JAXRSInInterceptor.handleMessage(JAXRSInInterceptor.java:88)
    org.apache.cxf.phase.PhaseInterceptorChain.doIntercept(PhaseInterceptorChain.java:255)
    org.apache.cxf.transport.ChainInitiationObserver.onMessage(ChainInitiationObserver.java:113)
    org.apache.cxf.transport.servlet.ServletDestination.invoke(ServletDestination.java:105)
    org.apache.cxf.transport.servlet.ServletController.invokeDestination(ServletController.java:461)
    org.apache.cxf.transport.servlet.ServletController.invoke(ServletController.java:188)
    org.apache.cxf.transport.servlet.AbstractCXFServlet.invoke(AbstractCXFServlet.java:148)
    org.apache.cxf.transport.servlet.AbstractHTTPServlet.handleRequest(AbstractHTTPServlet.java:179)
    org.apache.cxf.transport.servlet.AbstractHTTPServlet.doGet(AbstractHTTPServlet.java:108)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
    org.apache.cxf.transport.servlet.AbstractHTTPServlet.service(AbstractHTTPServlet.java:159)

那么，有没有办法在外部配置 XmlRoot 注解中的信息，这样我们就不用在 Java 代码中添加了呢？

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1 回答 1

1

来自关于jaxrs-data-bindings的 Apache-cxf 文档：

作为使用 @XmlRootElement 和 Collection 包装器的替代方法，可以提供一个对象工厂，它会告诉 JAXB 如何编组给定类型（在 Collections 的情况下 - 它的模板类型）。另一种选择是直接从/在给定方法中返回/接受 JAXBElement。

另一种选择是注册一个或多个能够为多种不同类型创建 JAXBContexts 的 JAX-RS ContextResolver 提供程序。默认 JAXBElementProvider 将在尝试自行创建 JAXBContext 之前首先检查这些解析器。

于 2012-11-12T12:02:45.607 回答