4

按照此处的示例，我轻松创建了我的小部件。

然后我在我的小部件中添加了一个按钮，这个按钮应该启动一个服务，所以我将以下代码添加到我的 WidgetProvider

@Override
public void onEnabled(Context context) {
    Log.e("ERROR", "REMOVE ME"); // TODO remove. This is for eclipse logcat recognition
    RemoteViews views = new RemoteViews(context.getPackageName(), R.layout.widget_layout);

    Intent intent = new Intent(context, RepairService.class);
    PendingIntent pi = PendingIntent.getService(context, 0, intent, 0);
    views.setOnClickPendingIntent(R.id.widget_boost, pi);
}

代码肯定会被调用，但服务没有启动。我确定我可能错过了服务 PendingIntent 的实现，但我看不到什么。还有人知道吗？

4

1 回答 1

5

好吧，我已经设法解决了

public class WidgetProvider extends AppWidgetProvider {

@Override
  public void onUpdate(Context context, AppWidgetManager appWidgetManager,
      int[] appWidgetIds) {

    Log.e("ERROR", "onUpdate method called");

    final int N = appWidgetIds.length;

    // Perform this loop procedure for each App Widget that belongs to this provider
    for (int i=0; i<N; i++) {
        int appWidgetId = appWidgetIds[i];

        // Create an Intent to launch ExampleActivity
        Intent intent = new Intent(context, UpdateService.class);
        PendingIntent pendingIntent = PendingIntent.getService(context, 0, intent, 0);
        Log("Pending Intent = " + pendingIntent.toString());

        // Get the layout for the App Widget and attach an on-click listener to the button
        RemoteViews views = new RemoteViews(context.getPackageName(), R.layout.widget_layout);
        views.setOnClickPendingIntent(R.id.widge, pendingIntent);

        // Tell the AppWidgetManager to perform an update on the current App Widget
        appWidgetManager.updateAppWidget(appWidgetId, views);
    }

}

public static class UpdateService extends Service {

    @Override
    public void onCreate() {
              .........
              .........
           }

           // Service stuff here
   }
}

我不完全确定在 onEnable 中这样做有什么问题。也许有人可以解释为什么。

于 2012-11-12T16:36:00.630 回答