2

我昨晚发布了一个关于此的问题,但仍在苦苦挣扎。我需要首先按姓名(以这种格式姓氏,名字),然后按考试成绩对文本文件中的学生列表进行排序。我不知道文本文件中有多少学生,除了少于 100 个。我必须使用 compareTo 方法(我认为我做对了)和一个数组(我认为我没有m 正确使用它)。我已经连续几个小时一直在搞砸这个问题,但我似乎不明白。教科书似乎对我没有任何帮助。如何让我的应用程序类打印排序的学生姓名/成绩?

其他规范是获得分数的平均值,并在任何低于平均水平的分数旁边发表评论。但是,在我理顺排序之后,我可以继续工作。

这是我的代码...

 package CH11AS8App;

 import java.io.FileReader;
 import java.util.Arrays;
 import java.util.Comparator;
 import java.util.Scanner;


 public class kjkkkkkkkkkkk {

 public static void main( String[] args ) throws Exception {
    // TODO Auto-generated method stub

        Scanner aScanner = new Scanner(
                                 new FileReader("src//chapt11//ch11AS8data.txt"));



        int numOfStudents = 100;
        Student[] studentArray = new Student[numOfStudents];
        Scanner sc = null;

        int counter = 0;
        while (aScanner.hasNext()) {
            sc = new Scanner(aScanner.nextLine());
            String lastName = sc.next();
            String firstName = sc.next();
            int score = sc.nextInt();


            studentArray[counter++] = new Student(lastName, firstName, score);

            studentArray[counter] = new Student(lastName, firstName, score); 

            int average= 0;
            int sum = 0;
            sum += score; 
             if (counter < numOfStudents); 
            average = sum / counter;
            if (score <= (average - 10)) {
             System.out.println("Score 10 points under average");
            System.out.println("Student Average:" + average);
        }



            sc.close();


            // Display Welcome Message
            System.out.println("Welcome to the Student Scores Application.\n");

            //Sort Names
            Arrays.sort(studentArray,0,counter, new Comparator<Student>(){
                @Override
                public int compare(Student s1, Student s2) {
                    return s1.getLastName().compareTo(s2.getLastName());
                }
            });

            System.out.println();
            System.out.println("Student list by name:");
            System.out.println();
            for(int j = 0; j < counter; j++){  
                System.out.println(studentArray[j]);

            }

            //Sort Scores
            Arrays.sort(studentArray,0,counter, new Comparator<Student>(){
                @Override
                public int compare(Student s1, Student s2) {
                    return Integer.valueOf(s2.getScore()).
                                       compareTo(Integer.valueOf(s1.getScore()));
                }
            });


            System.out.println();
            System.out.println();
            System.out.println("Student list by score:");
            System.out.println();
            for(int j = 0; j < counter; j++){  
                System.out.println(studentArray[j]);

            }


            //Close Scanner
            aScanner.close();

}

static class Student implements Comparable<Student> {

    //Instance Variables
    private String firstName;
    private String lastName;
    private int score;

    //Getters & Setters
    public Student( String firstName, String lastName, int score ) {
        this.firstName = firstName;
        this.score = score;
        this.lastName = lastName;
    }
    public int getScore() {
        return score;
    }

    public String getFirstName() {
        return firstName;
    }

    public String getLastName() {
        return lastName;
    }


    //CompareTo Method
    @Override
    public int compareTo( Student s ) {

        if( !firstName.equalsIgnoreCase( s.firstName ) ) {

            return firstName.compareToIgnoreCase( s.firstName );
        }

        if( !lastName.equalsIgnoreCase( s.lastName ) ) {

            return lastName.compareToIgnoreCase( s.lastName );
        }
            return (new Integer(score)).compareTo((new Integer(s.score)));
    }
        @Override public String toString(){ return lastName + ", "+ firstName        +" : "+score; }


    }

 }
4

3 回答 3

4

您的错误在compareTo()方法的最后一行:

改变

return examScore = s.examScore;

return examScore - s.examScore;


您想返回差异,而不是设置实例变量!

于 2012-11-12T02:42:37.147 回答
1

我认为您应该更改 compareTo 中的最后一行,如下所示:

    return (new Integer(examScore)).compareTo((new Integer(s.examScore));

或者

    return Integer.valueOf(examScore).compareTo(Integer.valueOf(s.examScore));

这将比较两个值并相应地返回。

编辑:

您的程序中的一些更正:

  1. 在你的类中添加一个toString()方法:Student

    @Override public String toString(){ return firstName + " "+ lastName +" : "+examScore; }

  2. 更新main()应用程序中的方法如下:

    public static void main(String[] args) throws Exception {
    
        Scanner aScanner = new Scanner(
                               new FileReader("src//chapt11//ch11AS8data.txt"));
    
        System.out.println("Welcome to the Student Scores Application.\n");
    
        int nStudent = 100;
        Student[] studentArray = new Student[nStudent];
        Scanner lineScanner = null;
    
        int counter = 0;
        while (aScanner.hasNext()) {
            lineScanner = new Scanner(aScanner.nextLine());
            String lastName = lineScanner.next();
            String firstName = lineScanner.next();
            int examScore = lineScanner.nextInt();
            System.out.println("Student " + counter + " " + firstName + " "
                    + lastName + " " + +examScore);
    
            studentArray[counter++]=new Student(lastName, firstName, examScore);
            lineScanner.close();
        }
    
        for(int j = 0; j < counter; j++){  
            System.out.println(studentArray[j]);
        }
    
    
    
        //sort based on first name
        Arrays.sort(studentArray,0,counter, new Comparator<Student>(){
            @Override
            public int compare(Student s1, Student s2) {
                return s1.getFirstName().compareTo(s2.getFirstName());
            }
        });
        System.out.println("Students sorted by first name in ascending order");
        for(int j = 0; j < counter; j++){  
            System.out.println(studentArray[j]);
        }
    
        //sort based on score
        Arrays.sort(studentArray,0,counter, new Comparator<Student>(){
            @Override
            public int compare(Student s1, Student s2) {
                return Integer.valueOf(s1.getExamScore()).
                                   compareTo(Integer.valueOf(s2.getExamScore()));
            }
        });
        System.out.println("Students sorted by score in ascending order");
        for(int j = 0; j < counter; j++){  
            System.out.println(studentArray[j]);
        }
    
        //To compute the average:
        double sum = 0.0;
        for(int j = 0; j < counter; j++){  
            sum+=studentArray[j].getExamScore();
        }
        double average = (sum*1.0)/counter;
        System.out.println("Average Score = "+average );
    
    
        aScanner.close();
    }
    
于 2012-11-12T02:53:15.670 回答
0

因为这是家庭作业,所以我没有给你完整的答案……但这是你应该努力的总体思路……

import java.io.FileReader;
import java.util.Scanner;

public class App {

    public static void main( String[] args ) throws Exception {
        // TODO Auto-generated method stub

        Scanner aScanner = new Scanner( new FileReader( "src/scores.txt" ) );

        System.out.println( "Welcome to the Student Scores Application." );
        System.out.println();

        Student[] studentArray;

        String lastName;
        String firstName;
        int examScore = 0;
        double average = 0;

        int nStudent = 100;
        studentArray = new Student[nStudent];

        int counter = 0;

        while( aScanner.hasNext() ) {

            lastName = aScanner.next();
            firstName = aScanner.next();
            examScore = aScanner.nextInt();

            studentArray[counter] = new Student( lastName, firstName, examScore );

            System.out.println( "Student " + studentArray[counter].getFirstName() + " " +  studentArray[counter].getLastName() + "'s " + "Test Score is :" + studentArray[counter].getExamScore() );
            ++counter;
            if( counter >= nStudent ) {
                break;
            }
        }
    }

    static class Student implements Comparable<Student> {

        private String firstName;
        private String lastName;
        private int examScore;

        public Student( String firstName, String lastName, int examScore ) {
            this.firstName = firstName;
            this.examScore = examScore;
            this.lastName = lastName;
        }

        // Get & Set Methods
        public int getExamScore() {
            return examScore;
        }

        public String getFirstName() {
            return firstName;
        }

        public String getLastName() {
            return lastName;
        }

        @Override
        public int compareTo( Student s ) {

            if( !lastName.equalsIgnoreCase( s.lastName ) ) {

                return lastName.compareToIgnoreCase( s.lastName );
            }

            if( !firstName.equalsIgnoreCase( s.firstName ) ) {

                return firstName.compareToIgnoreCase( s.firstName );

            }

            return examScore - s.examScore;

        }

    }

}
于 2012-11-12T03:59:42.323 回答