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我正在创建一个要求用户输入用户名和密码的应用程序。一旦他们填写了文本字段，数据就会使用 GET 发送到 locahost。如果用户名和密码匹配，我的 php 设置为返回值 1，如果不匹配，则返回 2。但是，如果我尝试创建这样的 if 语句：if ([received isEqualTo:@"1"]) { NSLog(@"Access Granted"); }else{ NSLog(@"Access Denied"); }

它返回为拒绝访问，即使我执行 Nslog 它返回为 1 但它仍然没有说访问被授予。

这是 AppDelage.m：

 //
//  AppDelegate.m
//  possys
//
//  Created by  on 11/11/12.
//  Copyright (c) 2012 . All rights reserved.
//

#import "AppDelegate.h"

@implementation AppDelegate
@synthesize username;
@synthesize password;
@synthesize super;
@synthesize alert;
@synthesize connection = _connection;
@synthesize receivedData = _receivedData;

       - (void)applicationDidFinishLaunching:(NSNotification *)aNotification
    {
        // Insert code here to initialize your application
    }

    - (IBAction)login:(id)sender {
        NSString *user = [username stringValue];
        NSString *pass = [password stringValue];
        NSString *strurl = [NSString stringWithFormat:@"http://localhost/index.php?username=%@&password=%@",user,pass];
        [self.connection cancel];

        //initialize new mutable data
        NSMutableData *data = [[NSMutableData alloc] init];
        self.receivedData = data;


        //initialize url that is going to be fetched.
        NSURL *url = [NSURL URLWithString:strurl];

        //initialize a request from url
        NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];

        //initialize a connection from request
        NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self];
        self.connection = connection;


        //start the connection
        [connection start];


    }

    -(void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data{
            [self.receivedData appendData:data];

        }

    -(void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error{

            NSLog(@"%@" , error);
        }
    -(void)connectionDidFinishLoading:(NSURLConnection *)connection{

        //initialize convert the received data to string with UTF8 encoding
        NSMutableString *received = [[NSMutableString alloc] initWithData:self.receivedData
                                                  encoding:NSUTF8StringEncoding];
        NSLog(@"%@" , received);

        if ([received isEqualTo:@"1"]) {
            NSLog(@"YUPYUPYUP");
        }else{
            NSLog(@"YNO");
        }
    }

这是我的 php：

<?php 

   mysql_connect("localhost","root","abc123") or die (mysql_error());
   mysql_select_db("authentication") or die (mysql_error()); 

    $username = $_GET['username'];
    $password = $_GET['password'];


$username = stripslashes($username);
$password = stripslashes($password);


$sql = "select * from users where username = '$username' and password = '$password'";

$result = mysql_query($sql) or die (mysql_error());


$count = mysql_num_rows($result);

if ($count == 1) {
echo "1";
}

else{
    echo "2";

}

?>
4

2 回答 2

2

假设存在某种空白问题，您可以尝试：

if([received intValue] == 1)
    NSLog(@"YUPYUPYUP");
else
    NSLog(@"NO");

这样系统就会解析文本以获取一个数字，然后比较该数字，而不是寻找一个精确的字符串匹配。

于 2012-11-12T00:03:17.973 回答
2

尝试使用 isEqualToString: 方法而不是 isEqualTo:

    if ([received isEqualToString:@"1"]) {
        NSLog(@"YUPYUPYUP");
    }
    else{
        NSLog(@"YNO");
    }
于 2012-11-12T00:09:10.937 回答