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我正在尝试以以下形式生成 json 并将其发布到服务器：

{
"items":  [
 {
  "id": "3",
  "quantity": 0.5,
  "unit": "2"
 } ]
}

我正在使用ASIFormDataRequest. 我已经转义了 json 字符串，以便将其作为请求参数发送到 url

NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://api.esha.com/analysis?items=%@&apikey=%@",encodeJson,ApiKey]];
//here i have send escaped json (do I really need to do this thing?)

_request = [ASIFormDataRequest requestWithURL:url];
[_request setPostValue:jsonString forKey:@"items"]; //original json string
[_request setPostValue:ApiKey forKey:@"apikey"];
[_request setRequestMethod:@"POST"];
[_request addRequestHeader:@"Content-Type" value:@"application/json"];
[_request setDelegate:self];
_request.timeOutSeconds = 60.0; 
[_request startSynchronous];

作为回应，我收到 HTML 格式的“不支持的媒体类型”错误：

<body>
<h1>HTTP Status 415 - Unsupported Media Type</h1>
<HR size="1" noshade="noshade"><p><b>type</b>
Status report</p><p><b>message</b>
<u>Unsupported Media Type</u></p>
<p><b>description</b> <u>The server refused this request because the request entity is in a format not supported by the requested resource for the requested method (Unsupported Media Type).</u></p><HR size="1" noshade="noshade"><h3>Apache Tomcat/7.0.23</h3>
</body>

我会犯什么错误？谁能引导我走向正确的道路？谢谢。

4

1 回答 1

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最后我自己解决了。我的错误是我试图在请求的 URL 中发布 json（编码或什么），而服务器可能没有任何方法来支持这样的请求。我也试过ASIHTTPRequest，不知道为什么 ASIFormRequest 不起作用。现在我得到了回应。

所以我将上面的代码更改为：

NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://api.esha.com/analysis?apikey=%@",ApiKey]];

ASIHTTPRequest *request = [ASIHTTPRequest requestWithURL:url];
[request addRequestHeader:@"Content-Type" value:@"application/json"];
[request setPostBody:(NSMutableData *)[jsonString dataUsingEncoding:NSUTF8StringEncoding]];
[request setDelegate:self];
[request startSynchronous];
于 2012-11-10T16:26:14.397 回答