好的,假设我有两个实体,A 和 B。对于每个用户,可能有 0 个或多个 A,具有 UserId(外键)、GroupName 和 Name 属性的唯一组合。实体 A 还具有“值”属性。同样对于每个用户,可能有 0 个或多个 B,具有 UserID(同样是外键)和“Occurred”属性。
我的任务是找到所有 B 具有超过 7 天前的 Occurred 属性或具有超过现在的 Occurred 属性 - 特定 A 属性中的小时数。这段代码似乎完美地工作:
DateTime now = DateTime.UtcNow;
DateTime expired = now - TimeSpan.FromDays(7d);
using (DatabaseContext context = DatabaseContext.Create())
{
IQueryable<A> aQ = context.As.Where(a => a.GroupName == "Notifications" && s.Name == "Retention");
IQueryable<B> bQ = context.Bs.Where(
n => aQ.Any(a => a.UserId == b.UserId) ?
b.Occurred < EntityFunctions.AddHours(now, -aQ.FirstOrDefault(a => a.UserId == b.UserId).Value) :
b.Occurred < expired);
IList<B> bs = bQ.ToList();
// ...
}
这会产生一个 SQL 查询,如下所示:
SELECT
[Extent1].[ID] AS [ID],
[Extent1].[OCCURRED] AS [OCCURRED],
[Extent1].[USERID] AS [USERID],
FROM [dbo].[B] AS [Extent1]
OUTER APPLY (SELECT TOP (1)
[Extent2].[GROUPNAME] AS [GROUPNAME],
[Extent2].[NAME] AS [NAME],
[Extent2].[USERID] AS [USERID],
[Extent2].[VALUE] AS [VALUE],
FROM [dbo].[A] AS [Extent2]
WHERE (N'Notifications' = [Extent2].[GROUPNAME]) AND (N'Retention' = [Extent2].[NAME]) AND ([Extent2].[USERID] = [Extent1].[USERID]) ) AS [Element1]
OUTER APPLY (SELECT TOP (1)
[Extent3].[GROUPNAME] AS [GROUPNAME],
[Extent3].[NAME] AS [NAME],
[Extent3].[USERID] AS [USERID],
[Extent3].[VALUE] AS [VALUE],
FROM [dbo].[A] AS [Extent3]
WHERE (N'Notifications' = [Extent3].[GROUPNAME]) AND (N'Retention' = [Extent3].[NAME]) AND ([Extent3].[USERID] = [Extent1].[USERID]) ) AS [Element2]
WHERE (CASE WHEN ( EXISTS (SELECT
1 AS [C1]
FROM [dbo].[A] AS [Extent4]
WHERE (N'Notifications' = [Extent4].[GROUPNAME]) AND (N'Retention' = [Extent4].[NAME]) AND ([Extent4].[USERID] = [Extent1].[USERID])
)) THEN CASE WHEN ( CAST( [Extent1].[OCCURRED] AS datetime2) < (DATEADD (hours, -([Element1].[VALUE]), @p__linq__0))) THEN cast(1 as bit) WHEN ( NOT ( CAST( [Extent1].[OCCURRED] AS datetime2) < (DATEADD (hours, -([Element2].[VALUE]), @p__linq__0)))) THEN cast(0 as bit) END WHEN ([Extent1].[OCCURRED] < @p__linq__1) THEN cast(1 as bit) WHEN ( NOT ([Extent1].[OCCURRED] < @p__linq__1)) THEN cast(0 as bit) END) = 1
请注意,我已经从实际的东西中破解了代码和 SQL 查询,所以这可能不是完美的表示。但我希望它明白这一点:这看起来有点毛茸茸,至少在查询重复检查 A 以匹配组名、名称和用户的方式上。但我不是数据库专家。我所知道的是,一个观察到的执行运行了大约 2.5 秒。
有没有更好的方法来解决这个问题?
感谢您的任何意见!
- - 解决方案 - -
感谢格特。
代码的查询结果如下:
var bQ =
from b in context.Bs
let offset = aQ.FirstOrDefault(a => a.UserId == b.UserId)
let expiration = (null != offset) ? EntityFunctions.AddHours(now, -offset.Value) : expired
where b.Occurred < expiration
select b;
这几乎正是格特所建议的。新的 SQL 查询如下所示:
SELECT
[Extent1].[ID] AS [ID],
[Extent1].[OCCURRED] AS [OCCURRED],
[Extent1].[USERID] AS [USERID]
FROM [dbo].[B] AS [Extent1]
OUTER APPLY (SELECT TOP (1)
[Extent2].[GROUPNAME] AS [GROUPNAME],
[Extent2].[NAME] AS [NAME],
[Extent2].[USERID] AS [USERID],
[Extent2].[VALUE] AS [VALUE]
FROM [dbo].[A] AS [Extent2]
WHERE (N'Notifications' = [Extent2].[GROUPNAME]) AND (N'Retention' = [Extent2].[NAME]) AND ([Extent2].[USERID] = [Extent1].[USERID]) ) AS [Element1]
WHERE CAST( [Extent1].[OCCURRED] AS datetime2) < (CASE WHEN ([Element1].[ID] IS NOT NULL) THEN DATEADD (hour, -([Element1].[VALUE]), @p__linq__0) ELSE @p__linq__1 END)