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我尝试了各种方法。这对我来说很有意义，但是当我尝试执行时insert into listsandplayers，它告诉我不listID存在列。我用我的insert into listsandplayers陈述尝试了几种不同的方法，并继续得到这个错误。

我已经在这里发布了我认为该声明应该最有效的方式。这是此处显示的最后一条语句。

CREATE TABLE IF NOT EXISTS 
   lists (listID INTEGER NOT NULL PRIMARY KEY AUTOINCREMENT, listName VARCHAR(30));

CREATE TABLE IF NOT EXISTS 
   players(playerID INTEGER NOT NULL PRIMARY KEY AUTOINCREMENT, playerName VARCHAR);

CREATE TABLE IF NOT EXISTS 
    listsandplayers(listsandplayersID INTEGER NOT NULL, 
                    listID INTEGER REFERENCES lists (listID),  
                    playerID INTEGER REFERENCES players (playerID));

INSERT INTO lists (listName) VALUES('Los Angeles Dodgers');

INSERT INTO players (playerName) VALUES('Clayton Kershaw');

INSERT INTO listsandplayers (listID, playerID) VALUES(listID, playerID)   
WHERE listName = 'Los Angeles Dodgers'  
AND playerName = 'Clayton Kershaw'  
NATURAL JOIN lists  
NATURAL JOIN players;
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1 回答 1

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这不是命令的有效语法INSERT。试试这个：

INSERT INTO ListsAndPlayers (ListsAndPlayersID, ListID, PlayerID)
VALUES (42,
        (SELECT ListID FROM Lists WHERE ListName = 'Los Angeles Dodgers'),
        (SELECT PlayerID FROM Players WHERE PlayerName = 'Clayton Kershaw'));

如果您已将ListsAndPlayersID列声明为INTEGER PRIMARY KEY，SQLite 将自动生成一个值。（您也可以删除该ListsAndPlayersID列并仅使用ListIDandPlayerID的组合作为主键。）

于 2012-11-10T11:10:03.667 回答