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我有这种方法可以返回某个案例的所有党员，并且他们都返回以显示在一行中。我想把它分解，这样每一方都会有自己的一排。我并不是所有的各方都返回到一个列表然后显示该列表 - 我希望每一方都返回并继续循环，直到该案例的所有各方都返回一个单独的行。

当前方法返回列表中的所有各方：

public IList<Party> GetAssignedPartiesForThisAndAssociatedCases(Guid caseId, int officeId)
    {
        IQueryable<AssociatedCase> associatedCases = _associatedCaseService.GetAll(caseId, officeId);
        IQueryable<Case> cases = (associatedCases != null && associatedCases.Count() > 0)
                                     ? associatedCases.Select(a => a.Case)
                                     : _caseRepository.FindAll().Where(c => c.CaseId == caseId);
        var parties = new List<Party>();
        foreach (Case c in cases)
        {
            foreach (Appointment a in c.Appointments.Where(a => a.OfficeId == officeId))
            {
                foreach (AppointmentParty p in a.AppointmentParties.Where(ap=>ap.DateOff == null || ap.DateOff > DateTime.Today))
                {
                    AppointmentParty p1 = p;
                    if (!parties.Contains(p1.Party)) parties.Add(p1.Party);
                }
            }
        }
        return parties;
    }

目前，该方法将显示答案为：

案例#——案例名称——party1、party2、party3、party4、party5

我希望它显示为：

case # -- caseName -- party1
case # -- caseName -- party2
case # -- caseName -- party3
case # -- caseName -- party4
case # -- caseName -- party5

这是我的控制器中显示与各方的案例列表的部分：

 IEnumerable<AssociatedCase> associatedCases = _caseCompositeService.GetAssociatedCases(viewModel.CaseId,
                                                                                               _currentUser.OfficeId).Where(a=>a.CaseId != viewModel.CaseId);
        viewModel.AssociatedCases = associatedCases;

上面控制器中的 GetAssociatedCases 是从 CaseCompositeService 文件中调用的：

public IEnumerable<AssociatedCase> GetAssociatedCases(Guid caseId, int officeId)
    {
        IQueryable<AssociatedCase> associatedCases = _associatedCaseService.GetAll(caseId, officeId);
        return associatedCases;
    }

然后从 AssociatedCaseService 调用 GetAll 方法：

public IQueryable<AssociatedCase> GetAll(Guid caseId, int officeId)
    {
        AssociatedCase associatedCase =
            _associatedCaseRepository.FindAll().SingleOrDefault(a => a.OfficeId == officeId && a.CaseId == caseId);
        if (associatedCase == null) 
            return new List<AssociatedCase>().AsQueryable();
        return _associatedCaseRepository.FindAll().Where(a => a.AssociatedCaseId == associatedCase.AssociatedCaseId);
    }
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