197

我需要在禁用按钮上显示工具提示并在启用按钮上将其删除。目前，它反向工作。

扭转这种行为的最佳方法是什么？

$('[rel=tooltip]').tooltip();
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" rel="stylesheet"/>
<hr>
<button class="btn" disabled rel="tooltip" data-title="Dieser Link führt zu Google">button disabled</button>
<button class="btn" rel="tooltip" data-title="Dieser Link führt zu Google">button not disabled</button>

这是一个演示

PS：我想保留disabled属性。

4

19 回答 19

287

You can wrap the disabled button and put the tooltip on the wrapper:

<div class="tooltip-wrapper" data-title="Dieser Link führt zu Google">
  <button class="btn btn-default" disabled>button disabled</button>
</div>

If the wrapper has display:inline then the tooltip doesn't seem to work. Using display:block and display:inline-block seem to work fine. It also appears to work fine with a floated wrapper.

UPDATE Here's an updated JSFiddle that works with the latest Bootstrap (3.3.6). Thanks to @JohnLehmann for suggesting pointer-events: none; for the disabled button.

http://jsfiddle.net/cSSUA/209/

于 2013-11-12T19:21:35.200 回答
122

This can be done via CSS. The "pointer-events" property is what's preventing the tooltip from appearing. You can get disabled buttons to display tooltip by overriding the "pointer-events" property set by bootstrap.

.btn.disabled {
    pointer-events: auto;
}
于 2014-04-04T15:54:32.470 回答
28

If you're desperate (like i was) for tooltips on checkboxes, textboxes and the like, then here is my hackey workaround:

$('input:disabled, button:disabled').after(function (e) {
    d = $("<div>");
    i = $(this);
    d.css({
        height: i.outerHeight(),
        width: i.outerWidth(),
        position: "absolute",
    })
    d.css(i.offset());
    d.attr("title", i.attr("title"));
    d.tooltip();
    return d;
});

Working examples: http://jsfiddle.net/WB6bM/11/

For what its worth, I believe tooltips on disabled form elements is very important to the UX. If you're preventing somebody from doing something, you should tell them why.

于 2013-02-25T20:59:31.550 回答
19

Here is some working code: http://jsfiddle.net/mihaifm/W7XNU/200/

$('body').tooltip({
    selector: '[rel="tooltip"]'
});

$(".btn").click(function(e) {
    if (! $(this).hasClass("disabled"))
    {
        $(".disabled").removeClass("disabled").attr("rel", null);

        $(this).addClass("disabled").attr("rel", "tooltip");
    }
});

The idea is to add the tooltip to a parent element with the selector option, and then add/remove the rel attribute when enabling/disabling the button.

于 2012-11-09T21:17:59.623 回答
15

Based on Bootstrap 4

Disabled elements Elements with the disabled attribute aren’t interactive, meaning users cannot focus, hover, or click them to trigger a tooltip (or popover). As a workaround, you’ll want to trigger the tooltip from a wrapper or , ideally made keyboard-focusable using tabindex="0", and override the pointer-events on the disabled element.

<span class="d-inline-block" tabindex="0" data-toggle="tooltip" title="Disabled tooltip">
  <button class="btn btn-primary" style="pointer-events: none;" type="button" disabled>Disabled button</button>
</span>

All the details here: Bootstrap 4 doc

于 2020-05-07T14:02:54.653 回答
8

These workarounds are ugly. I've debugged the problem is that bootstrap automatically set CSS property pointer-events: none on disabled elements.

This magic property causes that JS is not able to handle any event on elements that matches CSS selector.

If you overwrite this property to default one, everything works like a charm, including tooltips!

.disabled {
  pointer-events: all !important;
}

However you shouldn't use so general selector, because you will probably have to manually stop JavaScript event propagation way you know (e.preventDefault()).

于 2015-06-01T08:57:55.087 回答
7

In my case, none of the above solutions worked. I found that it's easier to overlap the disabled button using an absolute element as:

<div rel="tooltip" title="I workz" class="wrap">
  <div class="overlap"></div>
  <button>I workz</button>
</div>

<div rel="tooltip" title="Boo!!" class="wrap poptooltip">
  <div class="overlap"></div>
  <button disabled>I workz disabled</button>
</div>

.wrap {
  display: inline-block;
  position: relative;
}

.overlap {
  display: none
}

.poptooltip .overlap {
  display: block;
  position: absolute;
  height: 100%;
  width: 100%;
  z-index: 1000;
}

Demo

于 2017-01-15T12:31:02.930 回答
6

Try this example:

Tooltips must be initialized with jQuery: select the specified element and call the tooltip() method in JavaScript:

$(document).ready(function () {
    $('[data-toggle="tooltip"]').tooltip();
});

Add CSS:

.tool-tip {
  display: inline-block;
}

.tool-tip [disabled] {
  pointer-events: none;
}

And your html:

<span class="tool-tip" data-toggle="tooltip" data-placement="bottom" title="I am Tooltip">
    <button disabled="disabled">I am disabled</button>
</span>
于 2017-03-24T09:30:45.287 回答
5

If it helps anyone, I was able to get a disabled button to show a tooltip by simply putting a span inside it and applying the tooltip stuff there, angularjs around it...

<button ng-click="$ctrl.onClickDoThis()"
        ng-disabled="!$ctrl.selectedStuff.length">
  <span tooltip-enable="!$ctrl.selectedStuff.length"
        tooltip-append-to-body="true"
        uib-tooltip="Select at least one thing to enable button.">
    My Butt
  </span>
</button>
于 2020-03-06T20:53:37.833 回答
4
于 2012-11-09T16:17:56.660 回答
4

You can simply override Bootstrap's "pointer-events" style for disabled buttons via CSS e.g.

.btn[disabled] {
 pointer-events: all !important;
}

Better still be explicit and disable specific buttons e.g.

#buttonId[disabled] {
 pointer-events: all !important;
}
于 2016-01-11T17:32:13.880 回答
2

This is what myself and tekromancr came up with.

Example element:

<a href="http://www.google.com" id="btn" type="button" class="btn btn-disabled" data-placement="top" data-toggle="tooltip" data-title="I'm a tooltip">Press Me</a>

note: the tooltip attributes can be added to a separate div, in which the id of that div is to be used when calling .tooltip('destroy'); or .tooltip();

this enables the tooltip, put it in any javascript that is included in the html file. this line might not be necessary to add, however. (if the tooltip shows w/o this line then don't bother including it)

$("#element_id").tooltip();

destroys tooltip, see below for usage.

$("#element_id").tooltip('destroy');

prevents the button from being clickable. because the disabled attribute is not being used, this is necessary, otherwise the button would still be clickable even though it "looks" as if it is disabled.

$("#element_id").click(
  function(evt){
    if ($(this).hasClass("btn-disabled")) {
      evt.preventDefault();
      return false;
    }
  });

Using bootstrap, the classes btn and btn-disabled are available to you. Override these in your own .css file. you can add any colors or whatever you want the button to look like when disabled. Make sure you keep the cursor: default; you can also change what .btn.btn-success looks like.

.btn.btn-disabled{
    cursor: default;
}

add the code below to whatever javascript is controlling the button becoming enabled.

$("#element_id").removeClass('btn-disabled');
$("#element_id").addClass('btn-success');
$('#element_id).tooltip('destroy');

tooltip should now only show when the button is disabled.

if you are using angularjs i also have a solution for that, if desired.

于 2014-07-28T17:19:17.913 回答
1

Working code for Bootstrap 3.3.6

Javascript:

$('body').tooltip({
  selector: '[data-toggle="tooltip"]'
});

$(".btn").click(function(e) {
 if ($(this).hasClass("disabled")){
   e.preventDefault();
 }
});

CSS:

a.btn.disabled, fieldset[disabled] a.btn {
  pointer-events: auto;
}
于 2016-04-28T09:43:04.917 回答
1

You can imitate the effect using CSS3.

Simply take the disabled state off the button and the tooltip doesn't appear anymore.. this is great for validation as the code requires less logic.

I wrote this pen to illustrate.

CSS3 Disabled Tooltips

[disabled] {
  &[disabled-tooltip] {
    cursor:not-allowed;
    position: relative;
    &:hover {
      &:before {
        content:'';
        border:5px solid transparent;
        border-top:5px solid black;
        position: absolute;
        left: 50%;
        transform: translate(-50%, calc(-100% + -5px));
      }
      &:after {
        content: attr(disabled-tooltip);
        position: absolute;
        left: 50%;
        transform: translate(-50%, calc(-100% + -15px));
        width:280px;
        background-color:black;
        color:white;
        border-radius:5px;
        padding:8px 12px;
        white-space:normal;
        line-height:1;
      }
    }
  }
}

<button type="button" class="btn btn-primary" disabled-tooltip="I am a disabled tooltip using CSS3.. You can not click this button." disabled>Primary Button</button>
于 2018-02-12T00:32:03.800 回答
1

Simply add the disabled class to the button instead of the disabled attribute to make it visibly disabled instead.

<button class="btn disabled" rel="tooltip" data-title="Dieser Link führt zu Google">button disabled</button>

Note: this button only appears to be disabled, but it still triggers events, and you just have to be mindful of that.

于 2019-09-23T03:37:57.280 回答
0

pointer-events: auto; does not work on an <input type="text" />.

I took a different approach. I do not disable the input field, but make it act as disabled via css and javascript.

Because the input field is not disabled, the tooltip is displayed properly. It was in my case way simpler than adding a wrapper in case the input field was disabled.

$(document).ready(function () {
  $('.disabled[data-toggle="tooltip"]').tooltip();
  $('.disabled').mousedown(function(event){
    event.stopImmediatePropagation();
    return false;
  });
});
input[type=text].disabled{
  cursor: default;
  margin-top: 40px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/tether/1.3.3/js/tether.min.js"></script>
<link href="//maxcdn.bootstrapcdn.com/bootstrap/3.3.1/css/bootstrap.min.css" rel="stylesheet"> 
<script src="//maxcdn.bootstrapcdn.com/bootstrap/3.3.1/js/bootstrap.min.js"></script>


<input type="text" name="my_field" value="100" class="disabled" list="values_z1" data-toggle="tooltip" data-placement="top" title="this is 10*10">

于 2016-07-20T12:10:58.387 回答
0

For Bootstrap 3

HTML

<button 
    class="btn btn-success" 
    disabled
    data-hint="Enabled">
  <div class="sp-btn-overlap" data-hint="Disabled"></div>
  Submit button
</button>

CSS

button { position:relative; }

.sp-btn-overlap { 
    position:absolute; 
    top:0; 
    left:0; 
    height:100%; 
    width:100%; 
    background:none; 
    border:none; 
    z-index:1900;
}

JS

$('button .sp-btn-overlap')
    .popover({
        trigger: 'hover',
        container: 'body',
        placement: 'bottom',
        content: function() {
            return $(this).parent().prop('disabled')
                    ? $(this).data('hint')
                    : $(this).parent().data('hint');
            }
        });


$('button .sp-btn-overlap')
  .popover({
    trigger: 'hover',
    container: 'body',
    placement: 'bottom',
    content: function() {
      return $(this).parent().prop('disabled')
                  ? $(this).data('hint')
                  : $(this).parent().data('hint'); }
  });
button {
  position:relative; /* important! */
}

.sp-btn-overlap {
  position:absolute;
  top:0;
  left:0;
  height:100%;
  width:100%;
  background:none;
  border:none;
  z-index:1900;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous">

<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js" integrity="sha384-Tc5IQib027qvyjSMfHjOMaLkfuWVxZxUPnCJA7l2mCWNIpG9mGCD8wGNIcPD7Txa" crossorigin="anonymous"></script>

<button disabled class="btn btn-default" data-hint="Enabled">
  <div class="sp-btn-overlap" data-hint="Disabled"></div>
  Disabled button
</button>

<button class="btn btn-default" data-hint="Enabled">
  <div class="sp-btn-overlap" data-hint="Disabled"></div>
  Enabled button
</button>

于 2018-05-16T12:49:11.420 回答
0

I finally solved this problem, at least with Safari, by putting "pointer-events: auto" before "disabled". The reverse order didn't work.

于 2019-10-19T23:39:01.537 回答
0

I had the same issue on Dynamic controls so I just simply do it by, Set style attributes and enable the read-only property = true when we need the element as disabled but show the tooltip if user click on the input button controls.

Yes disabled stopped all event functions like ObBlur, onClick /OnFocus. in place of below line :

((document.getElmentByName('MYINPUTBTN').item(0))).disabled= true;

we can do thru below code after that tooltip will be enabled in disabled input button elements.

((document.getElmentByName('MYINPUTBTN').item(0))).setAttribute("style", "background-color": #e9ecef;");

b

Hope this will resolve the issue.

于 2021-04-28T20:08:21.947 回答