6

我无法rledata.frame. 函数在另一组上效果很好:

fgroup <- aggregate(fevents2[,3:14], list(weeks = fevents2[, 1]), function(x) rle(x)$values)

这会产生错误:

Error in rle(x) : 'x' must be an atomic vector

样本数据:

> dput(fevents2[1:20,])
structure(list(weeks = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("1",
"2", "3", "4", "5", "6", "7"), class = "factor"), A1M.Date = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L), .Label = c("2012-05-09", "2012-05-10", "2012-05-11",
"2012-05-14", "2012-05-15", "2012-05-17", "2012-05-18", "2012-05-21",
"2012-05-22", "2012-05-24", "2012-05-25", "2012-05-28", "2012-05-29",
"2012-05-30", "2012-05-31", "2012-06-04", "2012-06-05", "2012-06-07",
"2012-06-08", "2012-06-11", "2012-06-12", "2012-06-14", "2012-06-15",
"2012-06-18", "2012-06-19", "2012-06-21", "2012-06-22"), class = "factor"),
    vv = structure(c(8L, 8L, 8L, 20L, 24L, 24L, 24L, 1L, 13L,
    13L, 13L, 13L, 13L, 13L, 13L, 13L, 13L, 13L, 13L, 24L), .Label = c("C AA",
    "C AJ", "C BB", "C BV", "C JA", "C JR", "C RJ", "C RR", "C RV",
    "C VB", "C VR", "C VV", "G AA", "G AJ", "G BB", "G BV", "G JA",
    "G JR", "G RJ", "G RR", "G RV", "G VB", "G VR", "nil"), class = "factor"),
    rv = structure(c(25L, 25L, 25L, 25L, 25L, 25L, 25L, 25L,
    10L, 10L, 22L, 22L, 22L, 25L, 10L, 22L, 22L, 22L, 22L, 25L
    ), .Label = c("C AA", "C AJ", "C BB", "C BV", "C JA", "C JR",
    "C RJ", "C RR", "C RV", "C VB", "C VR", "C VV", "G AA", "G AJ",
    "G BB", "G BV", "G JA", "G JR", "G RJ", "G RR", "G RV", "G VB",
    "G VR", "G VV", "nil"), class = "factor"), ja = structure(c(12L,
    12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 25L, 25L,
    12L, 24L, 24L, 24L, 24L, 24L, 24L), .Label = c("C AA", "C AJ",
    "C BB", "C BV", "C JA", "C JR", "C RJ", "C RR", "C RV", "C VB",
    "C VR", "C VV", "G AA", "G AJ", "G BB", "G BV", "G JA", "G JR",
    "G RJ", "G RR", "G RV", "G VB", "G VR", "G VV", "nil"), class = "factor"),
    aa = structure(c(2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 25L, 25L,
    25L, 25L, 25L, 25L, 25L, 25L, 25L, 25L, 25L, 25L), .Label = c("C AA",
    "C AJ", "C BB", "C BV", "C JA", "C JR", "C RJ", "C RR", "C RV",
    "C VB", "C VR", "C VV", "G AA", "G AJ", "G BB", "G BV", "G JA",
    "G JR", "G RJ", "G RR", "G RV", "G VB", "G VR", "G VV", "nil"
    ), class = "factor"), bv = structure(c(25L, 11L, 11L, 11L,
    23L, 23L, 23L, 23L, 23L, 23L, 23L, 23L, 23L, 23L, 23L, 23L,
    23L, 23L, 23L, 23L), .Label = c("C AA", "C AJ", "C BB", "C BV",
    "C JA", "C JR", "C RJ", "C RR", "C RV", "C VB", "C VR", "C VV",
    "G AA", "G AJ", "G BB", "G BV", "G JA", "G JR", "G RJ", "G RR",
    "G RV", "G VB", "G VR", "G VV", "nil"), class = "factor"),
    aj = structure(c(7L, 7L, 7L, 25L, 25L, 25L, 25L, 25L, 9L,
    9L, 21L, 21L, 21L, 21L, 21L, 21L, 21L, 21L, 25L, 25L), .Label = c("C AA",
    "C AJ", "C BB", "C BV", "C JA", "C JR", "C RJ", "C RR", "C RV",
    "C VB", "C VR", "C VV", "G AA", "G AJ", "G BB", "G BV", "G JA",
    "G JR", "G RJ", "G RR", "G RV", "G VB", "G VR", "G VV", "nil"
    ), class = "factor"), vb = structure(c(1L, 1L, 1L, 25L, 25L,
    25L, 25L, 25L, 25L, 25L, 25L, 25L, 25L, 25L, 25L, 25L, 2L,
    25L, 2L, 2L), .Label = c("C AA", "C AJ", "C BB", "C BV",
    "C JA", "C JR", "C RJ", "C RR", "C RV", "C VB", "C VR", "C VV",
    "G AA", "G AJ", "G BB", "G BV", "G JA", "G JR", "G RJ", "G RR",
    "G RV", "G VB", "G VR", "G VV", "nil"), class = "factor"),
    rj = structure(c(5L, 5L, 16L, 16L, 16L, 16L, 16L, 16L, 16L,
    16L, 16L, 16L, 16L, 16L, 16L, 16L, 16L, 16L, 16L, 16L), .Label = c("C AA",
    "C AJ", "C BB", "C BV", "C JR", "C RJ", "C RR", "C RV", "C VB",
    "C VR", "C VV", "G AA", "G AJ", "G BB", "G BV", "G JR", "G RJ",
    "G RR", "G RV", "G VB", "G VR", "G VV", "nil"), class = "factor"),
    rr = structure(c(3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L,
    3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L), .Label = c("C AA",
    "C AJ", "C BB", "C BV", "C JA", "C JR", "C RJ", "C RR", "C RV",
    "C VB", "C VR", "C VV", "G AA", "G AJ", "G BB", "G BV", "G JA",
    "G JR", "G RJ", "G RR", "G RV", "G VB", "G VR", "G VV", "nil"
    ), class = "factor"), vr = structure(c(5L, 5L, 5L, 25L, 25L,
    7L, 7L, 7L, 7L, 7L, 25L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L,
    7L), .Label = c("C AA", "C AJ", "C BB", "C BV", "C JA", "C JR",
    "C RJ", "C RR", "C RV", "C VB", "C VR", "C VV", "G AA", "G AJ",
    "G BB", "G BV", "G JA", "G JR", "G RJ", "G RR", "G RV", "G VB",
    "G VR", "G VV", "nil"), class = "factor"), bb = structure(c(4L,
    4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
    4L, 4L, 4L, 4L), .Label = c("C AA", "C AJ", "C BB", "C BV",
    "C JA", "C JR", "C RJ", "C RR", "C RV", "C VB", "C VR", "C VV",
    "G AA", "G AJ", "G BB", "G BV", "G JA", "G RJ", "G RR", "G RV",
    "G VB", "G VR", "G VV", "nil"), class = "factor"), jr = structure(c(25L,
    25L, 10L, 10L, 22L, 22L, 25L, 25L, 25L, 25L, 25L, 25L, 25L,
    25L, 25L, 25L, 5L, 5L, 5L, 5L), .Label = c("C AA", "C AJ",
    "C BB", "C BV", "C JA", "C JR", "C RJ", "C RR", "C RV", "C VB",
    "C VR", "C VV", "G AA", "G AJ", "G BB", "G BV", "G JA", "G JR",
    "G RJ", "G RR", "G RV", "G VB", "G VR", "G VV", "nil"), class = "factor")),
.Names = c("weeks",
"A1M.Date", "vv", "rv", "ja", "aa", "bv", "aj", "vb", "rj", "rr",
"vr", "bb", "jr"), row.names = c(NA, 20L), class = "data.frame")

数据结构:

str(fevents2)
data.frame':   1430 obs. of  14 variables:
 $ weeks   : Factor w/ 7 levels "1","2","3","4",..: 1 1 1 1 1 1 1 1 1 1 ...
 $ A1M.Date: Factor w/ 27 levels "2012-05-09","2012-05-10",..: 1 1 1 1 1 1 1 1 1 1 ...
 $ vv      : Factor w/ 24 levels "C AA","C AJ",..: 8 8 8 20 24 24 24 1 13 13 ..
 $ rv      : Factor w/ 25 levels "C AA","C AJ",..: 25 25 25 25 25 25 25 25 10 10 ...
 $ ja      : Factor w/ 25 levels "C AA","C AJ",..: 12 12 12 12 12 12 12 12 12 12 ...
 $ aa      : Factor w/ 25 levels "C AA","C AJ",..: 2 2 2 2 2 2 2 2 25 25 ...
 $ bv      : Factor w/ 25 levels "C AA","C AJ",..: 25 11 11 11 23 23 23 23 23 23 ...
 $ aj      : Factor w/ 25 levels "C AA","C AJ",..: 7 7 7 25 25 25 25 25 9 9 ...
 $ vb      : Factor w/ 25 levels "C AA","C AJ",..: 1 1 1 25 25 25 25 25 25 25 ...
 $ rj      : Factor w/ 23 levels "C AA","C AJ",..: 5 5 16 16 16 16 16 16 16 16 ...
 $ rr      : Factor w/ 25 levels "C AA","C AJ",..: 3 3 3 3 3 3 3 3 3 3 ...
 $ vr      : Factor w/ 25 levels "C AA","C AJ",..: 5 5 5 25 25 7 7 7 7 7 ...
 $ bb      : Factor w/ 24 levels "C AA","C AJ",..: 4 4 4 4 4 4 4 4 4 4 ...
 $ jr      : Factor w/ 25 levels "C AA","C AJ",..: 25 25 10 10 22 22 25 25 25 25 ...
NULL

我知道我有factors,但将factors 转换为numericwith

as.numeric(as.character(fevents2))

或者:

sapply(fevents2, function(x) as.numeric(as.character(x)))

不能解决我的问题:

Error in fevents3[, 3:14] : incorrect number of dimensions
In addition: Warning message:
In eval.with.vis(expr, envir, enclos) : NAs introduced by coercion

data.frame这是该rle函数工作的示例:

    dput(fevents[1:20,]
structure(list(weeks = c(1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1), A1M.Date = c("2012-05-09", "2012-05-09",
"2012-05-09", "2012-05-09", "2012-05-09", "2012-05-09", "2012-05-09",
"2012-05-09", "2012-05-09", "2012-05-09", "2012-05-09", "2012-05-09",
"2012-05-09", "2012-05-09", "2012-05-09", "2012-05-09", "2012-05-09",
"2012-05-09", "2012-05-09", "2012-05-09"), vv = c("C RR", "C RR",
"C RR", "G RR", "nil", "nil", "nil", "C AA", "G AA", "G AA",
"G AA", "G AA", "G AA", "G AA", "G AA", "G AA", "G AA", "G AA",
"G AA", "nil"), rv = c("nil", "nil", "nil", "nil", "nil", "nil",
"nil", "nil", "C VB", "C VB", "G VB", "G VB", "G VB", "nil",
"G VB", "G VB", "G VB", "G VB", "G VB", "nil"), ja = c("C VV",
"C VV", "C VV", "C VV", "C VV", "C VV", "C VV", "C VV", "C VV",
"C VV", "C VV", "nil", "nil", "G VV", "G VV", "G VV", "G VV",
"G VV", "G VV", "G VV"), aa = c("C AJ", "C AJ", "C AJ", "C AJ",
"C AJ", "C AJ", "C AJ", "C AJ", "nil", "nil", "nil", "nil", "nil",
"nil", "nil", "nil", "nil", "nil", "nil", "nil"), bv = c("nil",
"C VR", "C VR", "C VR", "G VR", "G VR", "G VR", "G VR", "G VR",
"G VR", "G VR", "G VR", "G VR", "G VR", "G VR", "G VR", "G VR",
"G VR", "G VR", "G VR"), aj = c("C RJ", "C RJ", "C RJ", "nil",
"nil", "nil", "nil", "nil", "C RV", "C RV", "G RV", "G RV", "G RV",
"G RV", "G RV", "G RV", "G RV", "G RV", "nil", "nil"), vb = c("C AA",
"C AA", "C AA", "nil", "nil", "nil", "nil", "nil", "nil", "nil",
"nil", "nil", "nil", "nil", "nil", "nil", "C AJ", "nil", "C AJ",
"C AJ"), rj = c("C JR", "C JR", "G JR", "G JR", "G JR", "G JR",
"G JR", "G JR", "G JR", "G JR", "G JR", "G JR", "G JR", "G JR",
"G JR", "G JR", "G JR", "G JR", "G JR", "G JR"), rr = c("C BB",
"C BB", "C BB", "C BB", "C BB", "C BB", "C BB", "C BB", "C BB",
"C BB", "C BB", "C BB", "C BB", "C BB", "C BB", "C BB", "C BB",
"C BB", "C BB", "C BB"), vr = c("C JA", "C JA", "C JA", "nil",
"nil", "C RJ", "C RJ", "C RJ", "C RJ", "C RJ", "nil", "C RJ",
"C RJ", "C RJ", "C RJ", "C RJ", "C RJ", "C RJ", "C RJ", "C RJ"
), bb = c("C BV", "C BV", "C BV", "C BV", "C BV", "C BV", "C BV",
"C BV", "C BV", "C BV", "C BV", "C BV", "C BV", "C BV", "C BV",
"C BV", "C BV", "C BV", "C BV", "C BV"), jr = c("nil", "nil",
"C VB", "C VB", "G VB", "G VB", "nil", "nil", "nil", "nil", "nil",
"nil", "nil", "nil", "nil", "nil", "C JA", "C JA", "C JA", "C JA"
)), .Names = c("weeks", "A1M.Date", "vv", "rv", "ja", "aa", "bv",
"aj", "vb", "rj", "rr", "vr", "bb", "jr"), row.names = c(NA,
20L), class = "data.frame")

str(fevents)
'data.frame':   1430 obs. of  14 variables:
 $ weeks   : num  1 1 1 1 1 1 1 1 1 1 ...
 $ A1M.Date: chr  "2012-05-09" "2012-05-09" "2012-05-09" "2012-05-09" ...
 $ vv      : chr  "C RR" "C RR" "C RR" "G RR" ...
 $ rv      : chr  "nil" "nil" "nil" "nil" ...
 $ ja      : chr  "C VV" "C VV" "C VV" "C VV" ...
 $ aa      : chr  "C AJ" "C AJ" "C AJ" "C AJ" ...
 $ bv      : chr  "nil" "C VR" "C VR" "C VR" ...
 $ aj      : chr  "C RJ" "C RJ" "C RJ" "nil" ...
 $ vb      : chr  "C AA" "C AA" "C AA" "nil" ...
 $ rj      : chr  "C JR" "C JR" "G JR" "G JR" ...
 $ rr      : chr  "C BB" "C BB" "C BB" "C BB" ...
 $ vr      : chr  "C JA" "C JA" "C JA" "nil" ...
 $ bb      : chr  "C BV" "C BV" "C BV" "C BV" ...
 $ jr      : chr  "nil" "nil" "C VB" "C VB" ...

我发现了一个非常“不优雅”的解决方法。data.frame以 CSV 格式写入文件并使用stringsAsFactors = FALSE. 这不是我想在我的代码中写的......必须有一种更简单的方法来重新排列的结构data.frame来取悦rle

4

1 回答 1

6

问题是一个因素*不是*一个原子向量,正如错误清楚地表明的那样。要么首先将所有因子转换为字符(而不是通过将它们强制转换为数字!),要么在正在应用的匿名函数中进行转换。

所以这个实现了第二个想法的方法是有效的:

aggregate(fevents2[,3:14], list(weeks = fevents2[, 1]),
          function(x) rle(as.character(x))$values)

时尚之后:

> aggregate(fevents2[,3:14], list(weeks = fevents2[, 1]),
+           function(x) rle(as.character(x))$values)
  weeks vv.1 vv.2 vv.3 vv.4 vv.5 vv.6 rv.1 rv.2 rv.3 rv.4 rv.5 rv.6 rv.7 ja.1
1     1 C RR G RR  nil C AA G AA  nil  nil C VB G VB  nil C VB G VB  nil C VV
  ja.2 ja.3 ja.4 aa.1 aa.2 bv.1 bv.2 bv.3 aj.1 aj.2 aj.3 aj.4 aj.5 vb.1 vb.2
1  nil C VV G VV C AJ  nil  nil C VR G VR C RJ  nil C RV G RV  nil C AA  nil
  vb.3 vb.4 vb.5 rj.1 rj.2   rr vr.1 vr.2 vr.3 vr.4 vr.5   bb jr.1 jr.2 jr.3
1 C AJ  nil C AJ C JR G JR C BB C JA  nil C RJ  nil C RJ C BV  nil C VB G VB
  jr.4 jr.5
1  nil C JA

虽然我不确定你期望得到什么 - 这里只有一周,aggregate并且rle已经将所有价值观融合在一起。您是否希望将要汇总$values的每个变量分开fevents2

另一件事:

as.numeric(as.character(fevents2))不可能工作,因为数据不是数字!而且您无法将这些功能应用于数据框并获得您想要的任何东西 - 如果它们完全有效。

sapply()件事应该工作。这是一个检查每个变量是否是一个因素的版本,如果是则强制它:

fevents3 <- sapply(fevents2,
                   function(x) if(is.factor(x)) { as.character(x) } else { x })

但是注意sapply()简化为一个矩阵,它将改变aggregate()调度的方法:

> class(fevents3)
[1] "matrix"

相反,也许

fevents3 <- lapply(fevents2,
                   function(x) if(is.factor(x)) { as.character(x) } else { x })
fevents3 <- data.frame(fevents3, stringsAsFactors = FALSE)

现在,如果您想应用 rle()到拆分数据的每一列并保持单独的情况如何

spl <- split(fevents3, list(weeks = fevents3[, 1]))
res <- lapply(spl, function(x) lapply(x[, 3:14], function(y) rle(y)$values))

这使

> res
$`1`
$`1`$vv
[1] "C RR" "G RR" "nil"  "C AA" "G AA" "nil" 

$`1`$rv
[1] "nil"  "C VB" "G VB" "nil"  "C VB" "G VB" "nil" 

$`1`$ja
[1] "C VV" "nil"  "C VV" "G VV"

$`1`$aa
[1] "C AJ" "nil" 

$`1`$bv
[1] "nil"  "C VR" "G VR"

$`1`$aj
[1] "C RJ" "nil"  "C RV" "G RV" "nil" 

$`1`$vb
[1] "C AA" "nil"  "C AJ" "nil"  "C AJ"

$`1`$rj
[1] "C JR" "G JR"

$`1`$rr
[1] "C BB"

$`1`$vr
[1] "C JA" "nil"  "C RJ" "nil"  "C RJ"

$`1`$bb
[1] "C BV"

$`1`$jr
[1] "nil"  "C VB" "G VB" "nil"  "C JA"

这与上面的答案相同aggregate(),但每个rle()输出都是分开的:

> unlist(res)
 1.vv1  1.vv2  1.vv3  1.vv4  1.vv5  1.vv6  1.rv1  1.rv2  1.rv3  1.rv4  1.rv5 
"C RR" "G RR"  "nil" "C AA" "G AA"  "nil"  "nil" "C VB" "G VB"  "nil" "C VB" 
 1.rv6  1.rv7  1.ja1  1.ja2  1.ja3  1.ja4  1.aa1  1.aa2  1.bv1  1.bv2  1.bv3 
"G VB"  "nil" "C VV"  "nil" "C VV" "G VV" "C AJ"  "nil"  "nil" "C VR" "G VR" 
 1.aj1  1.aj2  1.aj3  1.aj4  1.aj5  1.vb1  1.vb2  1.vb3  1.vb4  1.vb5  1.rj1 
"C RJ"  "nil" "C RV" "G RV"  "nil" "C AA"  "nil" "C AJ"  "nil" "C AJ" "C JR" 
 1.rj2   1.rr  1.vr1  1.vr2  1.vr3  1.vr4  1.vr5   1.bb  1.jr1  1.jr2  1.jr3 
"G JR" "C BB" "C JA"  "nil" "C RJ"  "nil" "C RJ" "C BV"  "nil" "C VB" "G VB" 
 1.jr4  1.jr5 
 "nil" "C JA" 
> aggregate(fevents2[,3:14], list(weeks = fevents2[, 1]),
+           function(x) rle(as.character(x))$values)
  weeks vv.1 vv.2 vv.3 vv.4 vv.5 vv.6 rv.1 rv.2 rv.3 rv.4 rv.5 rv.6 rv.7 ja.1
1     1 C RR G RR  nil C AA G AA  nil  nil C VB G VB  nil C VB G VB  nil C VV
  ja.2 ja.3 ja.4 aa.1 aa.2 bv.1 bv.2 bv.3 aj.1 aj.2 aj.3 aj.4 aj.5 vb.1 vb.2
1  nil C VV G VV C AJ  nil  nil C VR G VR C RJ  nil C RV G RV  nil C AA  nil
  vb.3 vb.4 vb.5 rj.1 rj.2   rr vr.1 vr.2 vr.3 vr.4 vr.5   bb jr.1 jr.2 jr.3
1 C AJ  nil C AJ C JR G JR C BB C JA  nil C RJ  nil C RJ C BV  nil C VB G VB
  jr.4 jr.5
1  nil C JA

[注意:这仅在这里是正确的,因为您显示的数据片段只有一周。我不记得unlist(res))如果超过一周会是什么样子。]

于 2012-11-09T16:51:26.280 回答