7

我有两张桌子。
一个是 answer_step_dtl
另一个是 tag_mst 如下 

Ans_code                      Ans_Desc
-------------------------------------------
50000000000000005770       Enter <B><APN></B> and press Ok.       
40000000000000000164       Enter <B><ACCOUNTNAME></B> in connection name.
40000000000000000165       Enter <B><ACCOUNTNAME></B> in <APN>.

等等。

我的 tag_mst 有这样的值

TAG_CODE                    TAG_NAME          TAG_VALUE
-------------------------------------------------------
100                          <APN>            EXAMPLE.COM
101                          <ACCOUNTNAME>    EXAMPLE

现在我的要求是我想选择带有标签桅杆替换值的答案表格答案表。一个 ans_desc 中可以有多个标签。

我在想办法

  1. 循环 answer_dtl 的结果，从单个记录中获取标签

  2. 循环遍历记录中的多个标签，然后替换标签

  3. 存储在临时表中，然后为新的临时表打开游标。

是不是这个方法。或者有什么简单的方法可以做到这一点。

4

2 回答 2

3

编辑：受@Rob van Wijk的注释启发，使用（递归）CTE 的奖励查询需要 11g（R2？）：

SQL> WITH data AS (
  2     SELECT ans_code, Ans_Desc, tag_name, tag_value,
  3            row_number() OVER (partition BY ans_code ORDER BY t.rowid) no,
  4            row_number() OVER
  5               (partition BY ans_code ORDER BY t.rowid DESC) is_last
  6        FROM answer_step_dtl a
  7        JOIN tag_mst t ON a.ans_desc LIKE '%' || t.tag_name || '%'
  8  ), n(ans_code, no, is_last, replaced) AS (
  9     SELECT ans_code, no n, is_last,
 10            replace (ans_desc, tag_name, tag_value) replaced
 11       FROM data
 12      WHERE no = 1
 13     UNION ALL
 14     SELECT d.ans_code, d.no, d.is_last,
 15            replace (n.replaced, d.tag_name, d.tag_value) replaced
 16       FROM data d
 17       JOIN n ON d.ans_code = n.ans_code
 18        AND d.no = n.no + 1
 19  )
 20  SELECT *
 21    FROM n
 22   WHERE is_last=1;

ANS_CODE             NO IS_LAST REPLACED
-------------------- -- ------- ---------------------------------------
40000000000000000164  1       1 Enter <B>EXAMPLE</B> in connection
50000000000000005770  1       1 Enter <B>EXAMPLE.COM</B> and press Ok.
40000000000000000165  2       1 Enter <B>EXAMPLE</B> in EXAMPLE.COM.

初步答案：

您可以使用 PL/SQL 函数。即使要替换多个标签，以下内容也将起作用：

CREATE OR REPLACE FUNCTION replacetags(p_desc VARCHAR2)
   RETURN VARCHAR2 IS
   l_result  LONG := p_desc;
   l_tag_pos INTEGER := 1;
   l_tag     tag_mst.tag_name%TYPE;
BEGIN
   LOOP
      l_tag     := regexp_substr(l_result, '<[^<]+>', l_tag_pos);
      l_tag_pos := regexp_instr(l_result, '<[^<]+>', l_tag_pos) + 1;
      EXIT WHEN l_tag IS NULL;
      BEGIN
         SELECT replace(l_result, l_tag, tag_value)
           INTO l_result
           FROM tag_mst
          WHERE tag_name = l_tag;
      EXCEPTION
         WHEN no_data_found THEN
            NULL; -- tag doesn't exist in tag_mst
      END;
   END LOOP;
   RETURN l_result;
END;

SQL> SELECT ans_code, replacetags(ans_desc)
  2    FROM answer_step_dtl;

ANS_CODE              REPLACETAGS(ANS_DESC)
--------------------- ----------------------------------------
50000000000000005770  Enter <B>EXAMPLE.COM</B> and press Ok.
40000000000000000164  Enter <B>EXAMPLE</B> in connection
40000000000000000165  Enter <B>EXAMPLE</B> in EXAMPLE.COM.
于 2012-11-09T09:30:00.893 回答
1

试试这个：

select d."Ans_code",replace("Ans_Desc","TAG_NAME","TAG_VALUE")
from   answer_step_dtl d, tag_mst m
where "Ans_Desc" like '%'|| "TAG_NAME" || '%'


SQL小提琴演示

于 2012-11-09T07:43:33.340 回答