我在脚本中进行了双重搜索。当它搜索玩家装备时,它将获取玩家 UID 并带回该玩家的姓名。唯一的问题是可能会返回超过 1 个结果,并且它只会显示最后一个带有名称的 UID。
$ip = "localhost";
$user = "******";
$pass = "*******";
$db = "hivemind";
$ill1 = $_POST['search'];
//Database Connection
$con = @mysql_connect("$ip:3316", "$user", "$pass")
or die(mysql_error());
//Select Database
$dbcon = @mysql_select_db($db, $con)
or die(mysql_error());
$sql = mysql_query("select PlayerUID, Inventory, Backpack from character_data where Inventory like '%$ill1%'");
while ($row = mysql_fetch_array($sql)) {
$puid = $row['PlayerUID'];
$inv = $row['Inventory'];
$back = $row['Backpack'];
?>
<html>
<body>
<table>
<tr>
<td><?php echo "$puid"; ?></td>
<td><?php echo "$inv"; ?></td>
<td><?php echo "$back"; ?></td>
</tr>
</table>
</body>
</html>
<?php }?>
<?php
//Database Connection
$con = @mysql_connect("$ip:3316", "$user", "$pass")
or die(mysql_error());
//Select Database
$dbcon = @mysql_select_db($db, $con)
or die(mysql_error());
$sql = mysql_query("select PlayerUID, PlayerName from player_data where PlayerUID like '%$puid%'");
while ($row = mysql_fetch_array($sql)) {
$puid2 = $row['PlayerUID'];
$plnm = $row['PlayerName'];
?>
<html>
<body>
<table>
<tr>
<td><?php echo "$puid"; ?></td>
<td><?php echo "$plnm"; ?></td>
</tr>
</table>
</body>
</html>
}