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我的问题是我是否正确使用 %s 或者它是否必须是我的变量的其他东西?(我的数据库中没有添加任何记录)

参赛作品:

$login = "coolkidz";
$sname = "heyu";
$city = "beautiful";
$pass = "awesome";
$username = "what";
$mcode = "nice";

查询

mysql_query("INSERT INTO login(sname, city, pass, username, mcode, username) VALUES('%s','%s','%s','%s','%s','%s')", $sname, $city, $pass, $username, $mcode, $login);

这是不发出任何东西的回声

echo "'INSERT INTO login(sname, city, pass, username, mcode, username) VALUES('%s','%s','%s','%s','%s','%s')', $sname, $city, $pass, $username, $mcode, $login");
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1 回答 1

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改成这样:

mysql_query("INSERT INTO login(sname, city, pass, username, mcode, username) VALUES('$sname','$city','$pass','$username','$mcode','$login')");
于 2012-11-09T04:32:02.290 回答