-3

可能重复:
能够在 print_r() 的输出中看到一个变量,但不确定如何在代码中访问它

stdClass Object ( [geonames] => Array ( [0] => stdClass Object ( [countryName] => United States [adminCode1] => TX [fclName] => city, village,... [countryCode] => US [lng] => -97.3455673 [fcodeName] => populated place [distance] => 1.83381 [toponymName] => Greenock [fcl] => P [name] => Greenock [fcode] => PPL [geonameId] => 4695037 [lat] => 31.7662717 [adminName1] => Texas [population] => 0 ) ) )

这是我从 print_r($results) 得到的结果。我需要获取 [name] 和 [adminname1] 值。我已经尝试了几种方法,结果我只是不断得到数组{或数组..任何帮助请

编辑:这是一个 var_dump:

object(stdClass)#1 (1) { ["geonames"]=> array(1) { [0]=> object(stdClass)#2 (15) { ["countryName"]=> string(13) "United States" ["adminCode1"]=> string(2) "TX" ["fclName"]=> string(17) "city, village,..." ["countryCode"]=> string(2) "US" ["lng"]=> float(-97.3455673) ["fcodeName"]=> string(15) "populated place" ["distance"]=> string(7) "1.83381" ["toponymName"]=> string(8) "Greenock" ["fcl"]=> string(1) "P" ["name"]=> string(8) "Greenock" ["fcode"]=> string(3) "PPL" ["geonameId"]=> int(4695037) ["lat"]=> float(31.7662717) ["adminName1"]=> string(5) "Texas" ["population"]=> int(0) } } }
4

1 回答 1

1

我认为这会做到:

$name = $object->geonames[0]->name;
$adminname1 = $object->geonames[0]->adminName1;

如果这不起作用,请将其分解为多个作业以查看哪里出错了:

$thing1 = $object->geonames;
$thing2 = $thing1[0];
$name = $thing2->name;

这在哪一步会出错?

于 2012-11-09T00:00:15.583 回答